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ra1l [238]
1 year ago
7

If a polynomial function, f(x), with rational coefficients has roots 3 and startroot 7 endroot, what must also be a root of f(x)

?
Mathematics
1 answer:
mezya [45]1 year ago
6 0

The conjugate which is 3 - √7 is also a root of f(x).

<h3>What is the root of a polynomial function?</h3>

The root of a polynomial function f(x) is the value of x for which f(x) = 0.

Now if a polynomial function has a root x = a + √b then the conjugate of x which is x' = a - √b is also a root of the function, f(x).

<h3>What must also be a root of f(x)?</h3>

Given that the polynomial function, f(x), with rational coefficients has roots

3 + √7, then by the above, the conjugate which is 3 - √7 is also a root of f(x).

So, 3 - √7 is also a root of f(x).

Learn more about root of a polynomial function here:

brainly.com/question/2833285

#SPJ1

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Answer: The  below figure shows the graph of the given situation.

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Then, the function of the given situation can be written as,

f(x)=48 - 6 x,     ------ (1)

where,  x is the number of hours and f(x) is the number of brownies Caroline has left in x hour.

Thus by substitution x= 0,1,2,3,4,5,6,7,8 in equation (1),

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With help of the above points we can draw the graph of the given situation.

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