Complete question is;
Multiple-choice questions each have 5 possible answers, one of which is correct. Assume that you guess the answers to 5 such questions.
Use the multiplication rule to find the probability that the first four guesses are wrong and the fifth is correct. That is, find P(WWWWC), where C denotes a correct answer and W denotes a wrong answer.
P(WWWWC) =
Answer:
P(WWWWC) = 0.0819
Step-by-step explanation:
We are told that each question has 5 possible answers and only 1 is correct. Thus, the probability of getting the right answer in any question is =
(number of correct choices)/(total number of choices) = 1/5
Meanwhile,since only 1 of the possible answers is correct, then there will be 4 incorrect answers. Thus, the probability of choosing the wrong answer would be;
(number of incorrect choices)/(total number of choices) = 4/5
Now, we want to find the probability of getting the 1st 4 guesses wrong and the 5th one correct. To do this we will simply multiply the probabilities of each individual event by each other.
Thus;
P(WWWWC) = (4/5) × (4/5) × (4/5) × (4/5) × (1/5) = 256/3125 ≈ 0.0819
P(WWWWC) = 0.0819
Given:
To find:
The value of 
.
Solution:
We have,
Using properties of log, we get
![\left[\because \log_a\dfrac{m}{n}=\log_am-\log_an\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbecause%20%5Clog_a%5Cdfrac%7Bm%7D%7Bn%7D%3D%5Clog_am-%5Clog_an%5Cright%5D)
![[\log x^n=n\log x]](https://tex.z-dn.net/?f=%5B%5Clog%20x%5En%3Dn%5Clog%20x%5D)
Substitute and .
Therefore, the value of is 
.
Answer:3/20
Step-by-step explanation:
Fraction of total area mowed = (3/5) + (1/4) = 17/20
Therefore fraction of total area left = 1 - (17/20) = (20/20) - (17/20) = 3/20
5x5 - 10x = 0
5x5 - 10x = 5x • (x4 - 2)
After 1 hour, 360 g decays to 180 g.
After another hour (total 2 hours), 180 g decays to 90 g.
After another hour (total 3), 90 g decays to 45 g.
After one more (total 4), 45 g decays to 22.5 g.
More quickly, with a half-life of 1 hour, the 360 g of starting material decays to
(360 g) / 2⁴ = 22.5 g
In general, if the half-life is 1 hour, then after <em>n</em> hours, an initial amount <em>A</em> of this substance decays according to
<em>A</em> / 2<em>ⁿ</em>
