Question

Beth and Sarah are selling candy for a school fundraiser. Customers can buy small boxes of candy and large boxes of candy. Beth sold 9 small boxes of candy and 10 large boxes of candy for a total of $297. Sarah sold 8 small boxes of candy and 5 large boxes of candy for a total of $194.
What is the cost of one small box of candy, and what is the cost of one large box of candy?

Hint: Solve a system of two equations using the elimination method.

Answer 1

Answer:

Cost of small box = $13

Cost of large box = $18

Step-by-step explanation:

Let the cost of small box of candy = $s

And the cost of large candy box = $b

Beth sold 9 small and 10 large boxes of candies for $297.

9s + 10b = 297 -----(1)

Sarah sold 8 small and 5 large boxes of candies for $194.

8s + 5b = 194 -------(2)

Multiply equation (2) by 2 then subtract equation (1) from (2).

2(8s + 5b) - (9s + 10b) = (2×194) - 297

16s + 10b - 9s - 10b = 388 - 297

7s = 91 ⇒ s = $13

From equation (2),

(8×13) + 5b = 194

104 + 5b = 194

5b = 90

b = $18