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klio [65]
3 years ago
13

Beth and Sarah are selling candy for a school fundraiser. Customers can buy small boxes of candy and large boxes of candy. Beth

sold 9 small boxes of candy and 10 large boxes of candy for a total of $297. Sarah sold 8 small boxes of candy and 5 large boxes of candy for a total of $194.
What is the cost of one small box of candy, and what is the cost of one large box of candy?

Hint: Solve a system of two equations using the elimination method.
Mathematics
1 answer:
Scrat [10]3 years ago
6 0

Answer:

Cost of small box = $13

Cost of large box = $18

Step-by-step explanation:

Let the cost of small box of candy = $s

And the cost of large candy box = $b

Beth sold 9 small and 10 large boxes of candies for $297.

9s + 10b = 297 -----(1)

Sarah sold 8 small and 5 large boxes of candies for $194.

8s + 5b = 194 -------(2)

Multiply equation (2) by 2 then subtract equation (1) from (2).

2(8s + 5b) - (9s + 10b) = (2×194) - 297

16s + 10b - 9s - 10b = 388 - 297

7s = 91 ⇒ s = $13

From equation (2),

(8×13) + 5b = 194

104 + 5b = 194

5b = 90

b = $18

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If I don't read carefully, I often make mistakes on my work.
velikii [3]

Answer:

compound sentence

Step-by-step explanation:

4 0
3 years ago
monique has 3/4 of tissues. if she cuts half of those tissues how much did she cut? put the answer in a fraction and percentage(
skelet666 [1.2K]

The required fraction of the tissue she cut is 3 /8, and the percentage is 37.5%.

Given that,
Monique has 3/4 of tissues. she cuts half of those tissues

<h3>What is the fraction?</h3>

Fraction is defined as the number of compositions that constitute the Whole.

Here,
Let the number of tissue be x,
She has 3 / 4 of the tissues = 3 / 4 x
she cuts half of those tissues = 1 / 2 * 3 / 4 * x
                                             = 3/8x or 37.5% of x

Thus, the required fraction of the tissue she cut is 3 /8, and the percentage is 37.5%.

Learn more about fractions here:
brainly.com/question/10708469

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4 0
1 year ago
Solve for k.<br><br> 9 + 3k = 15<br><br> k =
-Dominant- [34]

Answer:

k = 2

Step-by-step explanation:

subtract 9 from both sides and you have 3k=6

then divide by three on both sides to get 2

7 0
3 years ago
Read 2 more answers
The maximum acceptable level of a certain toxic chemical in vegetables has been set at 0.4 parts per million (ppm). A consumer h
Elodia [21]

Answer:

Null hypothesis : \mu \leq 0.4

Alternative hypothesis: \mu >0.4

And for this case a type of error I for this case would be reject the null hypothesis that the population mean is lower or equal than 0.4 when actually is true.

A Type I error would occur if, in fact, μ ≤ 0.4 ppm, but the results of the sampling lead to the conclusion that μ > 0.4 ppm

Step-by-step explanation:

Previous concepts

A hypothesis is defined as "a speculation or theory based on insufficient evidence that lends itself to further testing and experimentation. With further testing, a hypothesis can usually be proven true or false".  

The null hypothesis is defined as "a hypothesis that says there is no statistical significance between the two variables in the hypothesis. It is the hypothesis that the researcher is trying to disprove".  

The alternative hypothesis is "just the inverse, or opposite, of the null hypothesis. It is the hypothesis that researcher is trying to prove".  

Type I error, also known as a “false positive” is the error of rejecting a null  hypothesis when it is actually true. Can be interpreted as the error of no reject an  alternative hypothesis when the results can be  attributed not to the reality.  

Type II error, also known as a "false negative" is the error of not rejecting a null  hypothesis when the alternative hypothesis is the true. Can be interpreted as the error of failing to accept an alternative hypothesis when we don't have enough statistical power

Solution to the problem

For this case we are trying to check the following hypothesis:

Null hypothesis : \mu \leq 0.4

Alternative hypothesis: \mu >0.4

And for this case a type of error I for this case would be reject the null hypothesis that the population mean is lower or equal than 0.4 when actually is true.

A Type I error would occur if, in fact, μ ≤ 0.4 ppm, but the results of the sampling lead to the conclusion that μ > 0.4 ppm

7 0
3 years ago
1. Find the range of the function rule y = 5x – 2 for the domain.<br> (-5, -1, 0, 2, 10)
jeyben [28]
Range = (-27, -7, -2, 8, 48)
8 0
3 years ago
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