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Angelina_Jolie [31]
3 years ago
15

Helphelphelpjehkejjosndidnkdndjdndjfnkdndosndjjd

Mathematics
1 answer:
Hoochie [10]3 years ago
8 0
A'(1,-2)
B'(1,-3)
C'(-1,-3)
D'(-1,-2)
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REY [17]

Answer:

Step-by-step explanation:

Rationalize the denominator by multiplying both denominator & numerator by the conjugate of the denominator.

Conjugate of the denominator  1 + √3 is 1 - √3

\frac{6}{1+\sqrt{3}}=\frac{6(1-\sqrt{3})}{(1+\sqrt{3})(1-\sqrt{3})}\\\\=\frac{6(1-\sqrt{3})}{(1+\sqrt{3})(1-\sqrt{3})}\\\\=\frac{6(1-\sqrt{3})}{1^{2}-(\sqrt{3})^{2}}\\\\=\frac{6(1-\sqrt{3})}{1-3}\\\\=\frac{6(1-\sqrt{3})}{-2}\\\\=(-3)(1-\sqrt{3})\\\\=-3+3\sqrt{3}

3 0
3 years ago
Need help ASAP please and thank you!
erik [133]

Answer:

I believe that the answer is 153 units^2.

9*10=90

And then 9*7=63, since there are two of the same triangle, we don't have to divide by 2.

So, 90+63=153.

I hope this helps!

7 0
2 years ago
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0.\overline{7}=0.777...\\\\x=0.777...\qquad\text{multiply both sides by 10}\\\\10x=7.777...\\\\\text{Make the difference}\\\\10x-x=7.777...-0.777...\\\\9x=7\qquad\text{divide both sides by 9}\\\\x=\dfrac{7}{9}\\\\Answer:\ \boxed{0.\overline{7}=\dfrac{7}{9}}\\-----------------\\You\ can\ remember\\\\\dfrac{1}{9}=0.\overline{1}\\\\\dfrac{2}{9}=0.\overline{2}\\\\\dfrac{3}{9}=0.\overline{3}\\\\\dfrac{4}{9}=0.\overline{4}\\\vdots\\\\\dfrac{8}{9}=0.\overline{8}

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Step-by-step explanation:

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2 years ago
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