You can use the following equation:
10h+3p+0.5r=100
This equation uses “h” “p” and “r” to represent the number of animals bought, each variable having a coefficient which is that animal's price. The right side is the total price.
You will now need a second equation so you can proceed to substitution/elimination:
h+p+r=100
This equation, using the same variables, represents the total number of animals to be bought.
We can eliminate the “h” variable by multiplying the bottom equation by -10, you now have the following:
10h+3p+0.5r=100
-10h-10p-10r=-1000
Add down and the result is:
-7p-9.5r=-900
You can set up a proportion
-9.5r=-900+7p
r=(-900+7p)/-9.5
And substitute in the original equation…
P.S. I challenge you to figure out the rest on your own because it is really just a tedious process of substitution and elimination from here and my phone is about to die. I'll check in later if you're still having problems.
Answer:
C.)9
Step-by-step explanation:
You add up all your data to get 54 and divide by the amount of numbers you had in the data which was 6. So if you divide 54 by 6 you get 9.
Eleven is the sum. Add end is 7 and the ones is 4
Set this up as a proportion with seeds on top and plants on bottom. Ours will look like this:
. Cross multiply to get 12x=1092. Divide to get that the number of plants to expect from 156 seeds is 91, choice B from above.
Answer:
23. Calculate the P-value for this hypothesis test. Assume the requirements for the test are satisfied.
0.087
29. Which of the following pairs of hypotheses is the most appropriate for addressing this question?
H0:p=0.2 Ha:p>0.2
Step-by-step explanation
test statistic: 6.579
You reject Ha