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3 years ago

Seven pounds of grapes cost 10.43. How much would 3 pounds cost?

2 answers:

8 0

To answer this we will find the unit rate by dividing. Lets do it:-

10.43 ÷ 7 = 1.49
1 pound of grapes = $1.49

CHECK OUR WORK:-

1.49 × 7 = 10.43
we were RIGHT!!!

Now lets multiply to see how much 3 pounds would cost.

1.49 × 3 = 4.47

CHECK OUR WORK:-

4.47 ÷ 3 = 1.49
We were RIGHT!!

So, 3 pounds of grapes cost $4.47.

Hope i helped ya!!

sveticcg [70]3 years ago

8 0

3 pounds of grapes will cost $4.47.

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In this line of ,the ratio of red circles to blue circles is 1:3 , How many more red circles would need to be added to make the

avanturin [10]

8 more red circles because if you have 9 red circles and 3 blue ones the ratio would be 9:3 and if you simplify that down to 3:1 that’s the answer. So you would need to add 8 more red circles

5 0

3 years ago

MARSVECTORCALC6 3.4.020. My Notes A rectangular box with no top is to have a surface area of 64 m2. Find the dimensions (in m) t

ioda

Answer:

We would have

$l =w =\frac{8\sqrt{3}}{3} \\h = \frac{8\sqrt{3}}{6}$

where " l " is length, " w" is width and "h" is height.

Step-by-step explanation:

Step 1

Remember that

Surface area for a box with no top = $lw+2lh+2wh = 64$

where " l " is length, " w" is width and "h" is height.

Step 2.

Remember as well that

Volume of the box = $l*w*h$

Step 3

We can now use lagrange multipliers. Lets say,

$F(l,w,h) = lwh$

and

$g(l,w,h) = lw+2lh+2wh = 64$

By the lagrange multipliers method we know that

$\nabla F = \lambda \nabla g$

Step 4

Remember that

$\nabla F = (wh,lh,lw)$

and

$\nabla g = (w+2h,l+2h , 2w+2l)$

So basically you will have the system of equations

$wh = \lambda (w+2h)\\lh = \lambda (l+2h)\\lw = \lambda (2w+2l)$

Now, remember that you can multiply the first eqation, by "l" the second equation by "w" and the third one by "h" and you would get

$lwh = l\lambda (w+2h)\\\\lwh = w\lambda (l+2h)\\\\lwh = h\lambda (2w+2l)$

Then you would get

$l\lambda (w+2h) = w\lambda (l+2h) = h\lambda (2w+2l)$

You can get rid of $\lambda$ from these equations and you would get

$lw+2lh = lw+2wh = 2wh+2lh$

And from those equations you would get

$l = w =2h$

Now remember the original equation

$lw+2lh+2wh = 64$

If we plug in what we just got, we would have

$l^{2} + l^{2} + l^2 = 64 \\3l^{2} = 64 \\l = w = \frac{8\sqrt{3} }{3} \\h = \frac{8\sqrt{3} }{6}$

7 0

3 years ago

An insurance company has 10,000 automobile policyholders. The expected yearly claim per policyholder is $240, with a standard de

elena55 [62]

Answer:

almost 0%

Step-by-step explanation:

Given that for an insurance company with 10000 automobile policy holders, the expected yearly claim per policyholder is $240 with a standard deaviation of 800

using normal approximation, the probability that the total yearly claim exceeds $2.7 million is calculated as follows:

Sea sumatoria de x = SUMX, tenemos que:

$P (SUMX \geq 2700000) = P(\frac{SUMX - 240*10000}{800 *\sqrt{10000} } \geq \frac{2700000 - 240*10000}{800 *\sqrt{10000} })$