Fraction 3 over 4x = Fraction 1 over 5. x = ___?
2 answers:
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We know that
<span>foci on x-axis-------> is a ellipse with horizontal major axis
the equation is
(x</span>²/a²)+(y²/b²)=1
major axis is th<span>e </span>x<span>-axis with length </span><span>2<span>a
2a=14--------> a=7
</span></span>minor axis is the y<span>-axis with length </span><span>2<span>b
2b=4-----> b=2
the equation is
</span></span>(x²/a²)+(y²/b²)=1------> (x²/7²)+(y²/2²)=1-----> (x²/49)+(y²/4)=1
the answer is
(x²/49)+(y²/4)=1
see the attached figure
<span>foci on x-axis-------> is a ellipse with horizontal major axis
the equation is
(x</span>²/a²)+(y²/b²)=1
major axis is th<span>e </span>x<span>-axis with length </span><span>2<span>a
2a=14--------> a=7
</span></span>minor axis is the y<span>-axis with length </span><span>2<span>b
2b=4-----> b=2
the equation is
</span></span>(x²/a²)+(y²/b²)=1------> (x²/7²)+(y²/2²)=1-----> (x²/49)+(y²/4)=1
the answer is
(x²/49)+(y²/4)=1
see the attached figure
Answer:
Amount of input horsepower needed is 279.3 hp.
Step-by-step explanation:
if there is a loss of power of 5% the base horsepower will need to be increased by same percentage so that same amount of power can be delivered.
Now to calculate 5% of 266 hp, we can write
266 × = 13.3 hp
Now to deliver same amount of power we will have to add 5% of 266 hp to its actual power.
So real base power which is needed to deliver 266hp output even at a loss of 5% will be = (266+13.3) hp = 279.3 hp
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