To find the length of a line between two points with known x- and y- coordinates, use:
sqrt((change in x)^2 + (change in y)^2),
which I know may look confusing but it isn't really:
sqrt((5 - -3)^2 + (4 - -1)^2)
= sqrt(8^2 + 5^2)
= sqrt(64 + 25)
= sqrt(89)
x = dimes
y = quarters
We also know:
Dimes: 0.10
Quarters: 0.25
100 = x + y
So, 0.10x + 0.25y = 100
And, y = 100 - x
Let’s use substitution:
0.10x + 0.25( 100 - x ) = 100
= 0.10x + 25 - 0.25x = 100
= 25 - 100 = 0.25x - 0.10x
= (-75) = 0.15x
x = (-75) divide by 0.15
x = (-500)
Area is 20.4 units , thank me later
Answer:
SouthEast region
Step-by-step explanation:
#We need to find the truck density per region to be able to determine the most viable region for business:
![Density=\frac{mass}{Area}\\\\d_{NW}=\frac{320}{10972}=0.0293\ truck/sq \ mi\\\\d_{NE}=\frac{400}{9485}=0.0422\ truck/ sq \ mi\\\\d_{C}=\frac{480}{11645}=0.0412\ truck/sq \ mi\\\\d_{SW}=\frac{515}{11589}=0.0444 \ truck/sq \ mi\\\\d_{SE}=\frac{250}{9933}=0.0252 \ truck/sq \ mi](https://tex.z-dn.net/?f=Density%3D%5Cfrac%7Bmass%7D%7BArea%7D%5C%5C%5C%5Cd_%7BNW%7D%3D%5Cfrac%7B320%7D%7B10972%7D%3D0.0293%5C%20%20truck%2Fsq%20%5C%20mi%5C%5C%5C%5Cd_%7BNE%7D%3D%5Cfrac%7B400%7D%7B9485%7D%3D0.0422%5C%20truck%2F%20sq%20%5C%20mi%5C%5C%5C%5Cd_%7BC%7D%3D%5Cfrac%7B480%7D%7B11645%7D%3D0.0412%5C%20truck%2Fsq%20%5C%20mi%5C%5C%5C%5Cd_%7BSW%7D%3D%5Cfrac%7B515%7D%7B11589%7D%3D0.0444%20%5C%20truck%2Fsq%20%5C%20mi%5C%5C%5C%5Cd_%7BSE%7D%3D%5Cfrac%7B250%7D%7B9933%7D%3D0.0252%20%5C%20truck%2Fsq%20%5C%20mi)
SouthEast region has the lowest density of 0.0252 truck/sq mi hence the best region for expansion.
-A low food truck density is an indicator of a relatively low competition hence existance of a large market share yet to be dominated.
The slope-intercept form is y=mx + b, where m=slope and b=y-intercept. So,
the equation is y= -4x+2