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Black_prince [1.1K]
3 years ago
5

Jacob has several babysitting jobs.on one job ,he earned $10 an hour plus an extra $20 since there were 3 children.On another jo

b , he earned $15 an hour.He earned the same amount of money at both jobs .how many hours did he work and how much did he earned?
Mathematics
1 answer:
Umnica [9.8K]3 years ago
6 0

Answer:

4 hours, $60

Step-by-step explanation:

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PLZ answer quick!!!!!
Blizzard [7]

Number of items sold by Shelley = 3 items.

Let us assume cost of each item sold by Shelley = $ x each.

Total cost of 3 items for Shelly sold = 3*x = 3x.

Number of items sold by Billy Bob = 4 items.

The cost of each item sold by Billy Bob = $2.25 less than the items that Shelley bought = $(x-2.25) each.

Total cost of 4 items for Billy Bob sold = 4*(x-2.25) = 4(x-2.25).

Both Shelley and Billy Bob paid the same amount of money. So, we can setup an equation now.

a) Total cost of 4 items for Billy Bob sold=Total cost of 3 items for Shelly sold.

4(x-2.25) = 3x

b) Solving equation for x now.

Distributing 4 over (x-2.25), we get

4x - 4*2.25 = 3x.

4x -9 = 3x.

Adding 9 on both sides, we get

4x -9+9 = 3x+9

4x =3x+9.

Subtracting 3x from both sides, we get

4x-3x =3x-3x+9.

x = 9.

c) Checking the solution of the equation by plugging x=9 in equation we got above.

4(x-2.25) = 3x  => 4(9-2.25)= 3*9

               => 4*6.75 = 27

               => 27 = 27.

We got left side = right side. So the solution x=9 is correct.

d) The cost of each item sold by Billy Bob = 9-2.25 = $6.75

Therefore, the cost of each item sold by Shelley is $9 and cost of each item sold by Billy Bob is $6.75.

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Give the first ten terms of the following sequences. You can assume that the sequences start with an index of 1. Logs are to bas
Vitek1552 [10]

Answer:

a)

a1 = log(1) = 0 (2⁰ = 1)

a2 = log(2) = 1 (2¹ = 2)

a3 = log(3) = ln(3)/ln(2) = 1.098/0.693 = 1.5849

a4 = log(4) = 2 (2² = 4)

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a7 = log(7) = ln(7)/ln(2) = 1.9459/0.6932 = 2.807

a8 = log(8) = 3 (2³ = 8)

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b) I can take the results of log n we previously computed above to calculate 2^log(n), however the idea of this exercise is to learn about the definition of log_2:

log(x) is the number L such that 2^L = x. Therefore 2^log(n) = n if we take the log in base 2. This means that

a1 = 1

a2 = 2

a3 = 3

a4 = 4

a5 = 5

a6 = 6

a7 = 7

a8 = 8

a9 = 9

a10 = 10

I hope this works for you!!

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