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miskamm [114]
3 years ago
5

Emi computes the mean and variance for the population data set 87, 46, 90, 78, and 89. She finds the mean is 78. Her steps for f

inding the variance are shown below. What is the first error she made in computing the variance? Emi failed to find the difference of 89 - 78 correctly. Emi divided by N - 1 instead of N. Emi evaluated (46 - 78)2 as -(32)2. Emi forgot to take the square root of -135.6.
Mathematics
2 answers:
Nata [24]3 years ago
5 0
Mean = Sum of all the observations/ Number of observations = (87+46+90+78+89)/5 = 78

Variance = SD^2 ------ SD = Standard deviation

It means that with Variance, square root is never taken.

Therefore,
Variance = Summation of square of differences between observation and the mean divided by the number of observations.

That is,
 Variance = {(87-78)^2 + (46-78)^2 + (90-78)^2 + (78-78)^2 + (89-78)^2}/5 = 274
VladimirAG [237]3 years ago
3 0

Solution:

The Data set is , 87,46, 90, 78, 89.

Number of Observation = 5

Mean=\frac{\text{Sum of all the observation}}{\text{Total number of observation}} = \frac{87 + 46+90+78+89}{5}=\frac{390}{5}= 78

To find the Variance :

1. We have calculated mean.

2nd Step : From each Data set subtract mean in this way:

87 - 78 = 9, 46 -78 = -32, 90 - 78 = 12, 78 - 78 = 0, 89 - 78 = 11

3. Square the difference of Data and Mean.

(9)² = 81, (-32)²= 1024, (12)² = 144, 0² =0, (11)² = 121

4. Sum of all the Squared Data

81 + 1024 + 144 +0 + 121= 1370

5. Divide Sum of squared observation by 5.

We get = \frac{1370}{5} =274

6. Variance = √274 = 16.55 (approx)

Now the value of 89 - 78 is not given .So we can't say she had made the error or not.

As we have to divide the sum of squared observations by N , not N-1.This is the first error.

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