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Answer=140 fish
200 gallons of water in the first aquarium.
200 gallons of water in the second aquarium.
The first will be for the small fishes.
5 small fish x fish
_____________=__________
10 gallons 200 gallons
cross multiply
10x=1000
divide both sides by 10
x=100 small fish
The first aquarium has 100 small fish.
The second aquarium holds large fish.
8 large fish x fish
____________=___________
40 gallons 200 gallons
cross multiply
40x=1600
divide both sides by 40
x=40 large fish
The second aquarium has 40 large fish.
100small fish+40 large fish=140 total fish
Isiah is 5.83 miles away from his starting point.
When you draw the the miles Isaiah walks, you will discover that you are forming a right angle triangle.
To measure the length from the starting point to the ending point. We must used the Pythagorean equation. Where in the square of the hypotenuse is equal to the sum of squares of the other two sides.
a² + b² = c²
a = 3 miles 3² + 5² = c²
b = 5 miles 9 + 25 = c²
c = hypotenuse. 34 = c²
We must get the hypotenuse, since 34 is the square of the hypotenuse we must look for its square root.
c² = 34
c = √34
c = 5.83 miles
Answer:
Maximize C =
and x ≥ 0, y ≥ 0
Plot the lines on graph
So, boundary points of feasible region are (0,1.7) , (2.125,0) and (0,0)
Substitute the points in Maximize C
At (0,1.7)
Maximize C =
Maximize C =
At (2.125,0)
Maximize C =
Maximize C =
At (0,0)
Maximize C =
Maximize C =
So, Maximum value is attained at (2.125,0)
So, the optimal value of x is 2.125
The optimal value of y is 0
The maximum value of the objective function is 19.125
No, because negative base sometimes results in non-real or imaginary value.
