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Lilit [14]
3 years ago
5

Consider the formula for surface area

Mathematics
1 answer:
Tema [17]3 years ago
8 0

Answer:

C. in; in; in²

Step-by-step explanation:

Perimeter and height are given in regular units. Area is given in square units.

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Solve the proportion: 4/x = 2/7
N76 [4]

Answer:b

Step-by-step explanation:

4 0
3 years ago
Read 2 more answers
What multiple of 7 is also a factor of 7
enyata [817]
<span>The answer is 7. Seven is a prime number, which means that its multiples are 1 and itself (7): 7 = 1 * 7. To find out which one is a factor of 7, we should divide each of them by 7. 1/7 will be a decimal number and 7/7 = 1, which is a whole number. Thus, 7 will be a multiple of 7 and also a factor of 7.Hope this helps. Let me know if you need additional help!</span>
7 0
3 years ago
Question 2 Multiple Choice Worth 1 points)
Sati [7]

Comparing g(x) with f(x), you can see that the function f(x) is translated to the right by 6 units to produce g(x) which is equivalent to (x-6)²

<h3>Transformation of function</h3>

Transformation is a techniques use to change the position of an object on an xy-plane.

Given the parent function f(x) = x² and the function g(x) = x²-12x +36

Factorize g(x);

g(x) = x²-6x-6x+36

g(x)=x(x-6)-6(x-6)

Group the terms to have;

g(x) = (x-6)²

Comparing g(x) with f(x), you can see that the function f(x) is translated to the right by 6 units to produce g(x) which is equivalent to (x-6)²

Learn more on transformation here: brainly.com/question/4289712
#SPJ1

4 0
2 years ago
The area of a square is 49 cm^2. What is the perimeter, in cm, of the square?
rewona [7]

Answer:

P = 28 cm

Step-by-step explanation:

The area of a square is

A = s^2 where s is the side length

49 = s^2

Taking the square root of each side

sqrt(49) = sqrt(s^2)

7 =s

Now find the perimeter of the square

P = 4s

P = 4(7)

P = 28 cm

6 0
3 years ago
Read 2 more answers
Match each expression in the left column with the correct product in the right column.
lesya692 [45]

Answer:

-6

-6i

6i

6

Step-by-step explanation:

1) √4 . √-3 . √-3

$ \sqrt{4} = 2 $

$ \sqrt{-3} . \sqrt{-3} = (\sqrt{-3})^2 $

$ \sqrt{4} . (\sqrt{-3})^2 = 2 \times -3 = $ -6

2) √-4 . √-3 . √-3

$ \sqrt{-4} = 2i $ .

Therefore, $ \sqrt{-4} . \sqrt{-3} . \sqrt{-3} = 2. \sqrt{-1}  \times -3 = 2i \times (-3) =  $ - 6i

3) √4 . √3 . √-3

$ \sqrt{4} = 2 $

$ \sqrt{3} . \sqrt{-3} = (\sqrt{3})^2 . \sqrt{-1} $

$ \implies 2 \times 3i = $ 6i

4) √4 . √3 . √3

$ \sqrt{4} = 2 $

$ \sqrt{3} . \sqrt{3} = (\sqrt{3})^2  = 3 $

Therefore, √4 . √3 . √3 = 2 . 3 = 6

5 0
3 years ago
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