Answer:
Michael 24
Noor 42
Step-by-step explanation:
Ratio is 4:7
The initial quatity is 4x and 7x
After giving 3 shares the quatities are
4x - 3 and 7x + 3
Set equal to the new ratio
(4x - 3) / (7x + 3) = 7 / 15
Cross multiply
15(4x - 3) = 7(7x + 3)
Distribute
60x - 45 = 49x + 21
Add 45 to both sides
60x = 49x + 66
Subtract 49x from both sides
11x = 66
Divide both sides by 11
x = 6
Therefor
4x = 4*6 = 24 <–––– Michael's initial quantity
7x = 7*6 = 42 <–––– Noor's initial quantity
Answer:
d
Step-by-step explanation:
it is 4/5ths of the answer towards one and the only other likely answer would seem as though b but b=9/10ths so D.
The length of the open pit is Area divided by width
A/w = L
L = (12x^2 + 8x)/4x
L = 12x^2 / 4x + 8x/4x
L = 3x + 2
The length of the back part that has to be sealed is 3x + 2 + 2 + 2 = 3x + 8
Area of the White part and the shaded part = L * W
W = 10x -1
L = 3x + 8
Area of the White Part and the Shaded Part = (10x - 1)(3x +8)
The Area of the Shaded Part + White Part = the total area.
Area of the Shaded Part + 12x^2 + 8x = (3x + 8) * (10x - 1)
Expand the right hand side.
Area of the Shaded Part + 12x^2 + 8x = 30x^2 - 3x + 80x - 8 Combine
Area of the Shaded Part + 12x^2 + 8x = 30x^2 + 77x - 8
Answer
Subtract 12x^2 + 8x From both sides.
Area of the Shaded Part = 30x^2 - 12x + 77x - 8x -8
Area of the Shaded Part = 18x^2 + 69x - 8 Answer
Answer:
The student must get at least 86 in the next text in order to get an upper A average.
Step-by-step explanation:
The scores in the three tests are: 91, 94 and 89
The average score here is = 91 (rounded off to nearest whole number)
In order to get an Upper A average after tackling the next test, the students total score in the four tests must be 90 × 4 = 360
Let's say the student scores x in the fourth test.
Then; 91 + 94 + 89 + x ≥ 360
274 + x ≥ 360
x ≥ 360 - 274
x ≥ 86
Answer:
These ratios are equivalent to one another
Step-by-step explanation:
There are a couple of ways you can go about solving it.
1) 20/5=4 and 60/15=4
2) 15/5=3 and 60/20=3