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2 years ago

If you brought 20 pears for $1.00. How much does each pear cost?

Mathematics

1 answer:

zloy xaker [14]2 years ago

3 0

Answer:

5 cent

Step-by-step explanation:

if you bought 20 pears divide the amount of money by the number of pears

I hope I'm right n this helps

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Answer this please I don't get it

Tcecarenko [31]

I hope this helps you 35+50=50+35=85

7 0

3 years ago

Carol and Jan leave from the same place and travel on the same road going the same direction. Carol walks at a rate of 2 miles p

kramer

Let, the time when <span>Jan cough up to Carol = x

We know, Distance = Speed * Time.

So, Equation would be: 2x + 5*2 = 6x

2x + 10 = 6x

6x - 2x = 10

4x = 10

x = 10/4 = 2.5

Distance traveled in that time = 2.5 * 6 = 15 miles

In short, Your Answer would be: 15 miles

Hope this helps!</span>

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3 years ago

What is the answer to solve -2=4r+s for s

sleet_krkn [62]

The answer is s= -(4r+2)

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3 years ago

Evaluate the surface integral:S

rjkz [21]

Assuming $S$ does not include the plane $z=0$ , we can parameterize the region in spherical coordinates using

$\mathbf r(u,v)=\left\langle3\cos u\sin v,3\sin u\sin v,3\cos v\right\rangle$

where $0\le u\le2\pi$ and $0\le v\le\dfrac\pi/2$ . We then have

$x^2+y^2=9\cos^2u\sin^2v+9\sin^2u\sin^2v=9\sin^2v$
$(x^2+y^2)=9\sin^2v(3\cos v)=27\sin^2v\cos v$

Then the surface integral is equivalent to

$\displaystyle\iint_S(x^2+y^2)z\,\mathrm dS=27\int_{u=0}^{u=2\pi}\int_{v=0}^{v=\pi/2}\sin^2v\cos v\left\|\frac{\partial\mathbf r(u,v)}{\partial u}\times \frac{\partial\mathbf r(u,v)}{\partial u}\right\|\,\mathrm dv\,\mathrm du$

We have

$\dfrac{\partial\mathbf r(u,v)}{\partial u}=\langle-3\sin u\sin v,3\cos u\sin v,0\rangle$
$\dfrac{\partial\mathbf r(u,v)}{\partial v}=\langle3\cos u\cos v,3\sin u\cos v,-3\sin v\rangle$
$\implies\dfrac{\partial\mathbf r(u,v)}{\partial u}\times\dfrac{\partial\mathbf r(u,v)}{\partial v}=\langle-9\cos u\sin^2v,-9\sin u\sin^2v,-9\cos v\sin v\rangle$
$\implies\left\|\dfrac{\partial\mathbf r(u,v)}{\partial u}\times\dfrac{\partial\mathbf r(u,v)}{\partial v}\|=9\sin v$

So the surface integral is equivalent to

$\displaystyle243\int_{u=0}^{u=2\pi}\int_{v=0}^{v=\pi/2}\sin^3v\cos v\,\mathrm dv\,\mathrm du$
$=\displaystyle486\pi\int_{v=0}^{v=\pi/2}\sin^3v\cos v\,\mathrm dv$
$=\displaystyle486\pi\int_{w=0}^{w=1}w^3\,\mathrm dw$

where $w=\sin v\implies\mathrm dw=\cos v\,\mathrm dv$ .

$=\dfrac{243}2\pi w^4\bigg|_{w=0}^{w=1}$
$=\dfrac{243}2\pi$

4 0

3 years ago

There are 8 performers who will present their comedy acts this weekend at a comedy club. One of the performers insists on being

Natalija [7]

Well, the keyword here is One of the performers insist on being the last.

So, the amount of performers that we can arrange freely is 7 performers.

Different ways we can schedule their appearance is :

7 ! = 7 x 6 x 5 x 4 x 3 x 2 x 1

= 5040

hope this helps

5 0

3 years ago