Answer: The answer is 80%.
Step-by-step explanation: Let us define the following events.
B = the event that the shirt is blue,
G = the event that the shirt is green
and
S = the event that the shirt is striped.
So, n(B) = 8, n(G) = 7, n(B and S) = 5, n(G and S) = 4.
n(S) = 5 + 4 = 9.
We have
![n(B\cup S)=n(B)+n(S)-n(B\cap S)=8+9-5=12.](https://tex.z-dn.net/?f=n%28B%5Ccup%20S%29%3Dn%28B%29%2Bn%28S%29-n%28B%5Ccap%20S%29%3D8%2B9-5%3D12.)
Therefore, the required probability is
![p=\dfrac{n(B\cup S)}{8+7}=\dfrac{12}{15}=\dfrac{4}{5}=0.8=80\%.](https://tex.z-dn.net/?f=p%3D%5Cdfrac%7Bn%28B%5Ccup%20S%29%7D%7B8%2B7%7D%3D%5Cdfrac%7B12%7D%7B15%7D%3D%5Cdfrac%7B4%7D%7B5%7D%3D0.8%3D80%5C%25.)
Thus, the answer is 80%.
That’s the equation for pi, but the simplified fraction is 22/3 (please mark brainliest)
Answer:
A) from the line of best fit, the approximately y-intercept is (0,1.8). This means without any practice, 1h.8 games are won.
B) slope: (5.6-1.8)/(2-0) = 1.9
y = 1.9x + 1.8
(Line of best fit)
x = 13,
y = 1.9(13) + 1.8 = 26.5
Predicted no. of games won after 13 months of practice is 26.5
Answer:
IQR: 20
Range: 52
Step-by-step explanation:
IQR = 88 - 68 = 20
Range = 100 - 48 = 52
You need to multiply the length and the width of the shape.