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xeze [42]
4 years ago
5

Given the following functions:

Mathematics
1 answer:
AysviL [449]4 years ago
7 0

Answer:

The composition of the two functions are (fog)(x)=f(g(x))=x^2-6x+9 and (gof)(x)=g(f(x))

Step-by-step explanation:

Given two functions are

f(x)=^2

and g(x)=x-3

Now to find the composition of f and composition of g and f

ie, (fog)(x)=f(g(x))

and (gof)(x)=g(f(x))

(fog)(x)=f(g(x))

           =f(x-3)

           =(x-3^2)

         Now to find the composition of f and composition of  =x^2-2x(3)+3^2

(fog)(x)=x^2-6x\div 9

(gof)(x)=g(f(x))

=g(x^2)

(gof)(x)=x^2-3

The composition of the two functions are (gof)(x)=g(f(x))=x^2-3

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In AUVW, m/U = (9x - 8)°, m/V = (2x + 2)°, and m/W = (3x + 4)º.<br> Find m/V.
yawa3891 [41]

Answer:

m∠V = 28°

Step-by-step explanation:

In ΔUVW:

  • m∠U = (9x - 8)°
  • m∠V = (2x + 2)°
  • m∠W = (3x + 4)°

To find the measure of angle V, first find the value of x.

<u>Interior angles of a triangle sum to 180°</u>.

⇒ m∠U + m∠V + m∠W = 180°

⇒ (9x - 8) + (2x + 2) + (3x + 4) = 180

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⇒ 14x - 2 = 180

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⇒ x = 13

<u>Substitute</u> the found value of x into the expression for angle V:

⇒ m∠V = 2(13) + 2

⇒ m∠V = 26 + 2

⇒ m∠V = 28°

Therefore, the measure of angle V is 28°.

Learn more about interior angles of a triangle here:

brainly.com/question/27682937

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