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trapecia [35]
4 years ago
12

Find parametric equations for the tangent line at the point (cos(3pi/6),sin(3pi/6), (3pi/6))

Mathematics
1 answer:
r-ruslan [8.4K]4 years ago
5 0
r(t)=(\cos{t},\sin{t},t)
\\r'(t)=(-\sin{t},\cos{t},1)
\\t= \frac{3\pi}{6} = \frac{\pi}{2}
\\ r'(t)=(-\sin{\frac{\pi}{2}},\cos{\frac{\pi}{2}},1)
\\ r'(t)=(-1,0,1)
\\
\\x=0+t(-1)=-t
\\y=1+t\times 0=1
\\z= \frac{\pi}{2} +t
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Find the volume. Round your answer to the nearest tenth.
Simora [160]

Answer:

94.6m³

Step-by-step explanation:

The diagram shown in this question is a trapezoidal prism.

The volume of a trapezoidal prism is calculated as:

L × H × (P + Q/2)

Where L = Length = 4m

H = Height = 4.3m

P = Base width = 8m

Q = Top width = 3m

The volume of the trapezoidal prism =

4 × 4.3 ×(8+3/2)

=4 × 4.3 ×(11/2)

= 94.6m³

Therefore, the volume of the trapezoidal prism to the nearest tenth = 94.6m³

4 0
3 years ago
A population of protozoa develops with a constant relative growth rate of 0.6137 per member per day. On day zero the population
Wewaii [24]

Answer:

The population size after seven days will be 171.

Step-by-step explanation:

The population of protozoa can be modeled by the following equation.

Q(t) = Q(0)(1+r)^{t}

In which Q(t) is the population after t days, Q(0) is the initial population and r is the growth rate.

In this problem, we have that:

Q(0) = 6, r = 0.6137

So

Q(t) = 6(1.6137)^{t}

Find the population size after seven days.

This is Q(7).

Q(7) = 6(1.6137)^{7} = 171

The population size after seven days will be 171.

7 0
3 years ago
The set {3, 5, ?} could not be the sides of a triangle.<br><br> 2<br> 7<br> 3<br> 5
tresset_1 [31]
7 and 2 cannot be the lengths as on a triangle they're two equal side so two 3s or two 5s
6 0
4 years ago
Read 2 more answers
Need help solving #7 please
ELEN [110]

Answer:

False

Step-by-step explanation:

The equation says 21 is greater than or equal to 27, so it is false

5 0
3 years ago
Help please! <br><br> Geometry R.10 Solve a right triangle
Len [333]
That is a 30 60 90 triangle
The "short" side (DE) equals the middle side (FE) times (1 / sq rt(3))
short side = 8 * sqrt(3) * (1 / sq rt(3) = 8
Hypotenuse (DF) is 2 times the short side which equals 16.

Source:
http://www.1728.org/trig2.htm



4 0
4 years ago
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