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Ksenya-84 [330]
2 years ago
11

Round 823 to the nearest ten

Mathematics
2 answers:
kirza4 [7]2 years ago
7 0

Answer:

820

Step-by-step explanation:

Find the number in the ten place 2 and look one place to the right for the rounding digit 3. Round up if this number is greater than or equal to

5 and round down if it is less than 5.

bulgar [2K]2 years ago
4 0

820

bc it is not 825 or higher it stays the same

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What is the solution to the system of equations
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line J passes through points (-6,1) and (-3,6) . Line m is parallel to line j and passes through point (15,-1).what is the equat
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Slope of the line J
(6-1) / (-3-(-6))
5 / 3

so
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If this line passes through (15,-1)
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equation is
y = (5/3)x - 26
7 0
3 years ago
What is the equation, in point-slope form, of the line that is perpendicular to the given line and passes through the
Svetradugi [14.3K]

keeping in mind that perpendicular lines have negative reciprocal slopes, hmmmm what's the slope of that line above anyway,

\bf (\stackrel{x_1}{1}~,~\stackrel{y_1}{-1})\qquad (\stackrel{x_2}{4}~,~\stackrel{y_2}{2}) ~\hfill \stackrel{slope}{m}\implies \cfrac{\stackrel{rise} {\stackrel{y_2}{2}-\stackrel{y1}{(-1)}}}{\underset{run} {\underset{x_2}{4}-\underset{x_1}{1}}}\implies \cfrac{2+1}{3}\implies 1 \\\\[-0.35em] ~\dotfill

\bf \stackrel{\textit{perpendicular lines have \underline{negative reciprocal} slopes}} {\stackrel{slope}{\underline{1}\implies \cfrac{\underline{1}}{1}}\qquad \qquad \qquad \stackrel{reciprocal}{\cfrac{1}{\underline{1}}}\qquad \stackrel{negative~reciprocal}{-\cfrac{1}{\underline{1}}\implies -1}}

so we're really looking for the equation of a line whose slope is -1 and runs through (2,5)

\bf (\stackrel{x_1}{2}~,~\stackrel{y_1}{5})~\hspace{10em} \stackrel{slope}{m}\implies -1 \\\\\\ \begin{array}{|c|ll} \cline{1-1} \textit{point-slope form}\\ \cline{1-1} \\ y-y_1=m(x-x_1) \\\\ \cline{1-1} \end{array}\implies y-\stackrel{y_1}{5}=\stackrel{m}{-1}(x-\stackrel{x_1}{2}) \\\\\\ y-5=-x+2\implies y=-x+7

8 0
3 years ago
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An 8.0 kg block is moving at 3.2 m/s. A net force of 10 N is constantly applied on the block in the direction of its movement, u
Softa [21]

Answer:

5.02 m/s

Step-by-step explanation:

We are given that

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v=5.02 m/s

8 0
2 years ago
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