Please help simple math problem

Mathematics

2 answers:

GarryVolchara [31]3 years ago

4 0

The answer is supplementary angles, hopefully that helps.

pshichka [43]3 years ago

4 0

The answer to your question is (C) VERTICAL ANGLES

When 2 lines intersect, they make vertical angles.
Vertical angles are congruent (equal).
Vertical angles are opposite one another.Supplementary angles add up to 180º = 40 degrees + 140 degrees = 180 degrees. Adjacent and Supplementary Angles = 120 + 60 = 180 degreesAdjacent angles are “side by side” and share a common ray. 130 degrees and 50 degrees.Complementary angles add up to 90º. = 60 degrees + 30 degrees = 90 degrees.

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Write an ordered pair for each point graphed below.

Viefleur [7K]

Answer:

$\boxed{(-1,4)}$

Step-by-step explanation:

The point is located in Quadrant II of the graph, where x-values are negative and y-values are positive.

Each marking on the graph represents one unit of distance. The two axes meet at the origin, where the coordinate point is equal to $(0,0)$ .

So, you can count backwards once from the origin to get your x-value ⇒ $-1$ and count up upwards four times from $x=-1$ to get your y-value ⇒ $4$ .

Finally, place these in a coordinate point $(x,y)$ ⇒ $\boxed{(-1,4)}$ .

5 0

3 years ago

Read 2 more answers

BRAINLY FOR THE FASTEST WITH GOOD EXPLANATIONS

Neporo4naja [7]

So, when we're tasked with things like this, rewriting everything in terms of sine and cosine and combining fractions often trivializes things, so doing just that gives us:

$\frac{\frac{1}{\cos{x}}-\frac{1}{\sin{x}}}{\frac{\cos{x}}{\sin{x}}-1}= \\\frac{\frac{=(\cos{x}-\sin{x})}{\cos{x}\sin{x}}}{\frac{\cos{x}}{\sin{x}}-\frac{\sin{x}}{\sin{x}}}=\\\frac{-(\cos{x}-\sin{x})}{\cos{x}\sin{x}}*\frac{\sin{x}}{\cos{x}-\sin{x}}=\\-\frac{1}{\cos{x}}$