Answer: Option b.
Step-by-step explanation:
First, you need to calculate the ratio of the area. This is:

You know that the area of the smaller trapezoid is 771 m², then you can set up the following proportion, where "x" is the area of the larger trapezoid. Then you have:

Now you must solve for "x". Therefore, you get that the area of the larger trapezoid is:

43 divided by 50 equals to 0.86
Answer:
The rate of change of the tracking angle is 0.05599 rad/sec
Step-by-step explanation:
Here the ship is traveling at 15 mi/hr north east and
Port to Radar station = 2 miles
Distance traveled by the ship in 30 minutes = 0.5 * 15 = 7.5 miles
Therefore the ship, port and radar makes a triangle with sides
2, 7.5 and x
The value of x is gotten from cosine rule as follows
x² = 2² + 7.5² - 2*2*7.5*cos(45) = 39.04
x = 6.25 miles
By sine rule we have

Therefore,

α = Angle between radar and ship α
∴ α = 58.052
Where we put
to get
and differentiate to get
= 3.208 degrees/second = 0.05599 rad/sec.
Answer:
x=32
Step-by-step explanation:
2x^2 because you do (-4x^2)-x=(-6x^2) and solve for x to get 2x^2.