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bija089 [108]
3 years ago
14

Tickets for an American Baseball League game for 3 adults and 3 children cost less than $75, while tickets for 2 adults and 4 ch

ildren cost less than $62. Could the tickets cost $20 for adults and $8 for children?
Mathematics
1 answer:
nikitadnepr [17]3 years ago
4 0
<h3>No, the cost of 1 adult ticket cannot be $ 20 and the cost of 1 children ticket is not $ 8.</h3>

Step-by-step explanation:

Let us assume the cots of ticket for 1 adult  = $ x

Let us assume the cots of ticket for 1 children  = $ y

So, the cost of ticket for 3 adults = 3 x ( Cost of 1 adult ticket) =  3 x

The cost of ticket for 3 children  = 3 x ( Cost of 1 children ticket)  =  3 y

Also, given the combined cost of 3 adult and children ticket is less than $75.

⇒  3 x +  3  y < 75  ... (1)

Similarly,  the cost of ticket for 2 adults = 2 x

The cost of ticket for 4 children   = 4 y

⇒  2 x +  4  y < 62  ... (2)

Now, solving for the values of x and y, we get:

3 x + 3 y < 75 or, x + y < 25   ⇒ x = 25 - y ( substitute in 2)

2 x +  4  y < 62  or, x +  2 y < 31

⇒   25  - y + 2 y < 31

or, y + 25 < 31

or, y < 6

⇒ x = 25 - 6  = 19

or, x < 19

So, the cost of 1 adult ticket  is x and is less than $19.

The cost of 1 child ticket  is y  and is less than $6.

Hence, by above statement, NO the cost of 1 adult ticket  can not be $ 20 and the cost of 1 children ticket is not $ 8.

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Answer:

case a) The approximate circumference of circle is 5.9\ units and the ratio of circumference to Diameter is \frac{C}{D}=2.95

case b) The approximate circumference of circle is 6\ units and the ratio of circumference to Diameter is \frac{C}{D}=3

case c) The approximate circumference of circle is 6.24\ units and the ratio of circumference to Diameter is \frac{C}{D}=3.12

Step-by-step explanation:

we know that

The approximate circumference of each circle, is equal to the perimeter of each inscribed polygon

case A) the figure is an inscribed pentagon

step 1

Find the approximate circumference of circle

The perimeter of the pentagon is equal to

P=5s

where

s=1.18\ units

substitute

P=5(1.18)=5.9\ units

therefore

The approximate circumference of circle is 5.9\ units

step 2

Find the ratio of circumference to Diameter

we know that

The radius is half the diameter so

D=2r=2(1)=2\ units

The ratio is equal to

\frac{C}{D}=5.9/2=2.95

case B) the figure is an inscribed hexagon

step 1

Find the approximate circumference of circle

The perimeter of the hexagon is equal to

P=6s

where

s=1\ units

substitute

P=6(1)=6\ units

therefore

The approximate circumference of circle is 6\ units

step 2

Find the ratio of circumference to Diameter

we know that

The radius is half the diameter so

D=2r=2(1)=2\ units

The ratio is equal to

\frac{C}{D}=6/2=3

case C) the figure is an inscribed dodecahedron

step 1

Find the approximate circumference of circle

The perimeter of the dodecahedron is equal to

P=12s

where

s=0.52\ units

substitute

P=12(0.52)=6.24\ units

therefore

The approximate circumference of circle is 6.24\ units

step 2

Find the ratio of circumference to Diameter

we know that

The radius is half the diameter so

D=2r=2(1)=2\ units

The ratio is equal to

\frac{C}{D}=6.24/2=3.12

<em>Conclusion</em>

We  know that

The exact value of the ratio \frac{C}{D} is equal to

\frac{\pi D}{D}=\pi

The approximate value of the circumference will be closer to the real one when the number of sides of the inscribed polygon is greater

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