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Fynjy0 [20]
3 years ago
6

And some more help there are a few more

Mathematics
2 answers:
insens350 [35]3 years ago
6 0

(3x²y²)/(12x)

Divide each number and variable. Note that when you are dividing variables, you are subtracting the powers.

3/12 = 1/4

x²/x = x

Answer: (x(y²))/4

hope this helps

nadezda [96]3 years ago
3 0

\frac{3x^2y^2}{12x}

Divide the top and bottom by 3

\frac{3x^2y^2}{12x} will become \frac{x^2y^2}{4x}

Now take the x² from the top and subtract the exponents with the x on the bottom: x² - x = x

\frac{x^2y^2}{4x} should become \frac{xy^2}{4}

\frac{xy^2}{4} is your answer

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Ellen read a book a day for 10 weeks. How many books did<br> she read in all?
a_sh-v [17]

1 week = 7 days

10 weeks = 10×7 days

= 70 days

if Ellen reads 1 book in a day

Therefore,

1 day = 1 book

70 days = 70×1

= 70 books.

Thus Ellen reads 70 books in 10 weeks.

Hope helps

8 0
2 years ago
Read 2 more answers
Indicate whether the following congruence statement is true or false.<br> 50 points
Nostrana [21]

Step-by-step explanation:

Since line NL is not necessarily congruent to MQ (labelled with different congruent marks), triangle NLM is not congruent to triangle MQP.

Instead, triangles NLM and QPM are congruent.

8 0
3 years ago
Read 2 more answers
LT1 10th grade level
Anton [14]

Answer:

The distance between the pirate and the treasure can be found from the following relationship between ΔEAF and ΔABC;

\overline{AE}/\overline{AB} =  \overline{FA}/\overline{AC} = \overline{EF}/\overline{BC}

Step-by-step explanation:

From the question diagram, we have two triangles, ΔEAF and ΔABC;

The ratio of the lengths of the sides \overline{AE}/\overline{AB} =  \overline{FA}/\overline{AC}

∠EAF and ∠BAC are vertical angles, therefore ∠EAF = ∠BAC

Therefore, ΔEAF and ΔABC are similar triangles by Side-Angle-Side, SAS, rule of similarity which states that two triangles that have ratios of a pair of their corresponding sides and the two sides also form equal angles within each triangle, then the two triangles are similar

Therefore, the ratio of the each pair of corresponding sides of the two triangles are equal

We have;

\overline{AE}/\overline{AB} =  \overline{FA}/\overline{AC} = 50 ft. /(100 ft.) =  \overline{EF}/\overline{BC} = \overline{EF}/120 ft.

\overline{EF} = 120 ft. × 50 ft./(100 ft.) = 60 ft.

\overline{EF} = 60 ft.

The distance between the pirate and the treasure, \overline{EF} = 60 ft.

4 0
3 years ago
What is equal to 0/0<br><br> 0<br> 0<br> 0<br> none of the above
babunello [35]

Answer:

well um I have to go with 0

6 0
3 years ago
-(x-5)^(1/4)+(7/3)=2 solve for x
Arisa [49]
I think the answer is 406/81. 

5 0
4 years ago
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