F=ma
is the formula you need to find the amount of newtons force.
If it weighs 210, and it's being pulled down by gravity at 9.8m/s^2, all you have to do is multiply the two numbers to get 2058.
Answer:
Kinetic energy,
Explanation:
It is given that,
Mass of ball, m = 0.9 kg
It is dropped form a height of 7 m, h = 7 m
When the ball is at certain height it will have only potential energy. As it hits the ground, its potential energy gets converted to kinetic energy as per the law of conservation of energy.
So,
So, the kinetic energy when it hits the ground is 61.74 Joules.
1) G.mars= 9.8x(1/3)=3.26
Vi=10 m/s , T=12 sec
Dis. = Vi(t)+1/2(g)(t)^2
(10)(12)+1/2(3.26)(12)^2= 354.72
2)V=500 m/s
Hmax= v^/2(g) = 500^2/2(9.8) = 12755.1
Answer:A)For open pipe
1stπ=484cm
2nd wavelength=161.3cm
3rd is=96.8cm
B)For closed pipe
1st wavelength=242cm
2nd=121cm
3rd wavelength=80.7cm
Explanation:
An open pipe produces a standing waves whose wavelength is related to it's length(length of pipe) by nL/4=π ,where n represent odd integers 1,2,3...
So the first note called fundamental note or 1st Harmonic is L=π/ 4,121=π/ 4
π= 121×4=484cm
Third harmonic,L=3π /4
So π= 4l/3=4×121/3=161.3cm
The 3rd wavelength is
Fifth harmonic=
π =4l/5=4×121/5=96.8cm
For a pipe open at one end and closed at the other also called closed pipe
Fundamental note is
2L/n= π where n=1,2,3....ie integers
First wavelength
π=2L=2×121=242cm
Second wavelength
π=L=121cm
Third is
π=2L/3=2×121/3=80.7cm
Only the horizontal component of the tension force is performing work on the crate. This component has magnitude (50 N) cos(30°) = 25√3 N, so the work done is
(25√3 N) (10 m) = 250√3 N•m ≈ 433 J