Answer:
your not ugly you have beauty or handsomeness in your own way you just don't show or give effert trust me I used to say that until someone told me what I told you
Answer:
none of the above
Step-by-step explanation:
The problem as written cannot have any of the solutions offered.
For any of those choices, the right side expression will be irrational. The left side expression will be rational for any rational value of x, so cannot be equal to the right-side expression.
The solution is an irrational number near ...
x ≈ 1.33682898582
You can figure this out by setting up an equation and make
x= tens digit
y= ones digit
y + 8 =x (tens digit 8 more than ones)
also we know that
y>0
x>0
since the 10s digit and 1s digit cannot be more than one number, we can say
0 < y > 10
0 < x > 10
since x has to be greater than 0 but less than 10, there is only one number that would fit into the equation for y
2 + 8 = 10
(y cannot equal 2 because than x is equal to 10 and it must be less than)
1 + 8 = 9
( y can be 1 since x is less than 10)
so it would be
y= 1
x= 9
the number would be 91
hope this helped!
<span>The definition of a perfect cube is a number that is the result of multiplying an integer by itself three times
Hope it helps</span>
Answer:
r=0
Step-by-step explanation:
7r-5r+8=9r+8-r
This is already an equation
Combine like terms
2r+8 = 8r+8
Subtract 2r from each side
2r-2r +8 = 8r-2r +8
8 =6r+8
Subtract 8 from each side
8-8 = 6r+8-8
0 = 6r
Divide by 6
0/6 = 6r/6
0 =r