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Otrada [13]
4 years ago
15

If y varies jointly with x and y=5 when x=15 and z=24 find y when x=6 and z=14

Mathematics
1 answer:
Scorpion4ik [409]4 years ago
5 0

Answer:

if they vary together then y would be 2

Step-by-step explanation:

since they vary together 5 multiplied by 3 is 15 so you would divide 6 by 3 to get 2 the z is irrelevant because it has no relation to x or y

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Find the area - PLSS HELPP AND HURRY PLS
Vilka [71]

Answer:

40

Step-by-step explanation:

its just 4 x 10, move the triangle to the other side

unless its not a triangle lol

then i have no idea

4 0
3 years ago
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How’s everyone’s day?
andrew-mc [135]
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4 0
3 years ago
10x - 4y=-20<br> Please help find number that fit to x and y that get me -20
garik1379 [7]

Answer: (0, 5) and (-2, 0)

<u>Step-by-step explanation:</u>

10x - 4y = -20

Let x = 0, then 10(0) - 4y = -20

                                  -4y = -20

                               <u> ÷ -4 </u>   <u>÷ -4  </u>

                                     y = 5

Let y = 0, then 10x - 4(0) = -20

                         10x -  0    = -20

                      <u> ÷10           </u>    <u> ÷10   </u>

                             x         = -2

7 0
3 years ago
An Internet reaction time test asks subjects to click their mouse button as soon as a light flashes on the screen. The light is
Ganezh [65]

Answer:

(a) 0.20

(b) 31%

(c) 2.52 seconds

Step-by-step explanation:

The random variable <em>Y</em> models the amount of time the subject has to wait for the light to flash.

The density curve represents that of an Uniform distribution with parameters <em>a</em> = 1 and <em>b</em> = 5.

So, Y\sim Unif(1,5)

(a)

The area under the density curve is always 1.

The length is 5 units.

Compute the height as follows:

\text{Area under the density curve}=\text{length}\times \text{height}

                                          1=5\times\text{height}\\\\\text{height}=\frac{1}{5}\\\\\text{height}=0.20

Thus, the height of the density curve is 0.20.

(b)

Compute the value of P (Y > 3.75) as follows:

P(Y>3.75)=\int\limits^{5}_{3.75} {\frac{1}{b-a}} \, dy \\\\=\int\limits^{5}_{3.75} {\frac{1}{5-1}} \, dy\\\\=\frac{1}{4}\times [y]^{5}_{3.75}\\\\=\frac{5-3.75}{4}\\\\=0.3125\\\\\approx 0.31

Thus, the light will flash more than 3.75 seconds after the subject clicks "Start" 31% of the times.

(c)

Compute the 38th percentile as follows:

P(Y

Thus, the 38th percentile is 2.52 seconds.

4 0
3 years ago
Factor the trinomial below x^2-12+35
shusha [124]

Answer:

B

Step-by-step explanation:

Given

x² - 12x + 35

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x² - 12x + 35 = (x - 5)(x - 7) → B

8 0
3 years ago
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