Answer:
Formulas and Procedures: Outlier An extreme value in a set of data which is much higher or lower than the other numbers. ... Outliers affect the mean value of the data but have little effect on the median or mode of a given set of data.
Answer:
Her mistake is that she wrote a two in the tenths place and zero in the ones place.
Step-by-step explanation:
3 can't go into zero so she had to write a zero in the tenths place. And 3 can go into 6 two times so she must write a 2 in the ones place.
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Answer:
The answer is not there.
Step-by-step explanation:
-1 5/6 x 4 6/1
-(1 x 6 + 5/6) x (4 x 1 + 6)
-11/6 x 10
-110/6
Simplified
-55/3 or -18 1/3
Answer:
the equation of the hyperbola is;(x²/81) - (y²/1600) = 1
Step-by-step explanation:
We are given that the hyperbola has;
Centre; 0,0
Vertex; 9,0
Focus; 41,0
Thus,the vertex and focus are on the x-axis. Thus, the equation for the hyperbola will have the form;
(x²/a²) - (y²/b²) = 1
Since The vertex is (9,0),so
a = 9 and a² = 9² = 81
Also,Since The focus is (41,0),so
c = 41 and c² = 41² = 1681
Solving for b², we have;
b² = c² - a²
b² = 1681 - 81
b² = 1600
b = √1600
b = 40
Thus,equation of hyperbola is;
(x²/9²) - (y²/40²) = 1
Which gives;
(x²/81) - (y²/1600) = 1
