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DaniilM [7]
3 years ago
15

Vincent started the year with $231 in his account at the health spa. Each time he uses the spa, $6 is taken out of the account.

How many more times can he use the spa if he has already had $48 taken out of his account this year?
Mathematics
1 answer:
SpyIntel [72]3 years ago
6 0

Answer:

Vincent would have 30.5 more visits, but since you can't have half a visit technically speaking, round up to 31 if it is allowed.

Step-by-step explanation:

$231 - $48 = $183

$183 divided by $6 = 30.5

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29.5-(1.5x15)
= $7

Hence: he spent $7 on the student discount card.

I subtracted the amount he spent on 15 passes with the discount card from the total amount he spent to find the amount he spent on the discount card:)
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Show how to find the product of 16.2 x 4 using addition.
Zielflug [23.3K]
16.2 + 16.2 + 16.2 + 16.2 So your answer is 64.8
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3 years ago
I need help!
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The instantaneous rate of change of the function f(x) = −4x² − 3x + 1 at the point x = -3 is 21.

<h3>What is the instantaneous rate of change of the function at the given point?</h3>

The instantaneous rate of change is simply the change in the derivative value at a specific point.

Given the data in the question;

  • f(x) = −4x² − 3x + 1
  • Point x = -3

To determine the instantaneous rate of change of the function, first find the derivative of the function.

f(x) = −4x² − 3x + 1

Applying sum rule, with respect to x

d/dx[ -4x² ] + d/dx[ -3x ] + d/dx[ 1 ]

[ 2 × -4x¹ ] + [ 1 × -3x⁰ ] + d/dx[ 1 ]

[ -8x ] + [ -3 ] + d/dx[ 1 ]

-8x - 3 + d/dx[ 1 ]

Differentiate using constant rule

-8x - 3 + [ 0 ]

-8x - 3

f'(x) = -8x - 3

Next, plug x = -3 into the derivative and simplify.

f'(x) = -8x - 3

f'(-3) = -8(-3) - 3

f'(-3) = 24 - 3

f'(-3) = 21

Therefore, the instantaneous rate of change of the function f(x) = −4x² − 3x + 1 at the point x = -3 is 21.

Learn more about instantaneous rate of change here: brainly.com/question/28122560

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7 0
1 year ago
Evaluate the surface integral S F · dS for the given vector field F and the oriented surface S. In other words, find the flux of
Law Incorporation [45]

Answer:

Step-by-step explanation:

To solve this problem, we will use the following two theorems/definitions:

- Given a vector field F of the form (P(x,y,z),Q(x,y,z),W(x,y,z)) then the divergence of F denoted by \nabla \cdot F = \frac{\partial P}{\partial x}+\frac{\partial Q}{\partial y}}+\frac{\partial W}{\partial z}

- (Gauss' theorem)Given a closed surface S, the following applies

\int_{S} F\cdot \vec{n} dS = \int_{V} \nabla \cdot F dV

where n is the normal vector pointing outward of the surface and V is the volume bounded by the surface S.

Let us, in our case, calculate the divergence of the given field. We have that

\nabla \cdot F = \frac{\partial}{\partial x}(x)+\frac{\partial}{\partial y}(2y)+ \frac{\partial}{\partial z}(5z) = 1+2+5 = 8

Hence, by the Gauss theorem we have that

\int_{S} F\cdot \vec{n} dS = \int_{V} 8 dV = 8\cdot\text{Volume of V}

So, we must calculate the volume V bounded by the cube S.

We know that the vertices are located on the given points. We must determine the lenght of the side of the cube. To do so, we will take two vertices that are on the some side and whose coordinates differ in only one coordinate. Then, we will calculate the distance between the vertices and that is the lenght of the side.

Take the vertices (1,1,1) and (1,1-1). The distance between them is given by

\sqrt[]{(1-1)^2+(1-1)^2+(1-(-1)^2} = \sqrt[]{4} = 2.

Hence, the volume of V is 2\cdot 2 \cdot 2 = 8. Then, the final answer is

\int_{S} F\cdot \vec{n} dS =8\cdot 8 = 64

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the common difference is two of course

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