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artcher [175]
3 years ago
9

When responding to an emergency, you should: Act without thinking Follow appropriate procedures Do whatever you can Do nothing t

o help
Health
2 answers:
Evgen [1.6K]3 years ago
6 0
When responding to an emergency, you should follow the appropriate procedures.
Tju [1.3M]3 years ago
5 0
The answer is "Follow appropriate procedures". 

"Act without thinking" and "Do nothing to help" should be wrong for obvious reasons. "Do whatever you can" probably seems like a reasonable choice, but if you do whatever you can without following appropriate procedures, then you might end up making the situation worse than it already is. You could get in someone else's way, or do something that someone isn't expecting which could waste time or cause harm.
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Differentiate the following functions (i) x(1+x)^3​
statuscvo [17]

Answer:

\displaystyle y' = (1 + x)^2(4x + 1)

General Formulas and Concepts:

<u>Algebra I</u>

  • Terms/Coefficients
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  • Function Notation
  • Factoring

<u>Calculus</u>

Derivatives

Derivative Notation

Derivative Property [Addition/Subtraction]:                                                                \displaystyle \frac{d}{dx}[f(x) + g(x)] = \frac{d}{dx}[f(x)] + \frac{d}{dx}[g(x)]

Basic Power Rule:

  • f(x) = cxⁿ
  • f’(x) = c·nxⁿ⁻¹

Derivative Rule [Product Rule]:                                                                                \displaystyle \frac{d}{dx} [f(x)g(x)]=f'(x)g(x) + g'(x)f(x)

Derivative Rule [Chain Rule]:                                                                                       \displaystyle \frac{d}{dx}[f(g(x))] =f'(g(x)) \cdot g'(x)

Explanation:

<u>Step 1: Define</u>

<em>Identify</em>

y = x(1 + x)³

<u>Step 2: Differentiate</u>

  1. Product Rule [Derivative Rule - Chain Rule]:                                                  \displaystyle y' = \frac{d}{dx}[x] \cdot (1 + x)^3 + x \cdot \frac{d}{dx}[(1 + x)^3] \cdot \frac{d}{dx}[1 + x]
  2. Derivative Property [Addition/Subtraction]:                                                    \displaystyle y' = \frac{d}{dx}[x] \cdot (1 + x)^3 + x \cdot \frac{d}{dx}[(1 + x)^3] \cdot (\frac{d}{dx}[1] + \frac{d}{dx}[x])
  3. Basic Power Rule:                                                                                             \displaystyle y' = x^{1 - 1} \cdot (1 + x)^3 + x \cdot 3(1 + x)^{3 - 1} \cdot (0 + x^{1 - 1})
  4. Simplify:                                                                                                             \displaystyle y' = (1 + x)^3 + 3x(1 + x)^2
  5. Factor:                                                                                                               \displaystyle y' = (1 + x)^2 \bigg[ (1 + x) + 3x \bigg]
  6. Combine like terms:                                                                                         \displaystyle y' = (1 + x)^2(4x + 1)

Topic: AP Calculus AB/BC (Calculus I/I + II)

Unit: Derivatives

Book: College Calculus 10e

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Uterosacral ligament suspension and sacrospinous fixation.
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cita uno o piu personaggi dello sport che ti hanno influenzato in maniera positiva e racconta il perchè.​
maw [93]

Answer:

One of the sports personalities who positively motivated me to my experience was Jose Meolans and Michael Phelps, who are two swimmers who sacrificed enough in their achievements to get where they got to.

These sportsmen sacrificed routines, trips, meals, and even family or friends meetings in search of a dream, which is the gold medal in the Olympic games, which they did.

Michael Phelps achieved more medals than Jose Meolans, but both overcame the hydrodynamics of other competitors in the water, they have a lot of discipline when it comes to physical activity, passion and commitment.

Explanation:

These swimmers have been swimming for many years and were one of the greatest milestones in swimming.

It should also be borne in mind that not only their good predisposition to fulfill their dreams was what generated their success in sports, but also their physical conditions.

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3 years ago
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