Answer:
The correct option is A. x – 1 < n < 3x + 5
Step-by-step explanation:
In a triangle sum of any two sides is always greater than the third side.
Now, the sides of the triangle are given to be :
2x + 2, x + 3 , n
Now, first take 2x + 2 and x + 3 as two sides and the side of length n as third side.
By using the property that sum of two sides is always greater than the third side in a triangle.
⇒ 2x + 2 + x + 3 > n
⇒ 3x + 5 > n ......(1)
Now, take n and x + 3 as two sides and the side of length 2x + 2 as the third side of triangle.
So, by the property, we have :
n + x + 3 > 2x + 2
⇒ n > x - 1 ...........(2)
From both the equations (1) and (2) , We get :
x – 1 < n < 3x + 5
Therefore, The correct option is A. x – 1 < n < 3x + 5
Answer:
Just switch out the 6 and 4 flip them out I guess
Step-by-step explanation:
Interesting question. Let the 2 unknown sides be x and x+1.
Then (11 m)^2 + x^2 = sum of the squares of the 2 shortest sides
= (x+1)^2
121 + x^2 = x^2 + 2x + 1. Then 121 = 2x + 1, and 2x = 120, or x = 60.
Then the hyp. has length 60+1= 61.
We must check these results. Using the Pyth. Thm. (a^2 + b^2 = c^2),
11^2 + 60^2 = 61^2
121 + 3600 = 3721 This is true, so our answers are correct.
The longer side is 60 and the hyp. has length 61.
Answer:
n divided by 6 (n/6)
Step-by-step explanation:
Answer:
The parametric hypothesis tests that we introduced in Chapter 5 were all based upon the means of the sample and population.
