ANSWER
My answer is in the photo above
Answer: 0.205
Step-by-step explanation:
The probability in one flip is equal to 0.5.
Now, if we do 10 flips, we want 4 times that the coin ends in heads and the other 6 times it must end in tails, so the probability is:
0.5^4*0.5^6 = 0.5^10
Now, this is the case where in the first 4 flips we get heads and in the other 6 we get tails, but we have other ways to get only 4 heads (for example in the last 4 flips, 2 at the beginning and 2 at the end, etc)
So we also need to calculate all the possible permutations of 4 heads in 10 flips. this is:
C = 10!/(10 - 4)!*4! = (10*9*8*7)/(4*3*2*1) = 210
So the probability that we are looking for is:
P = (0.5^10)*210 = 0.205
Answer and working out attached below. Hope it helps.
Consecutive integers<span> are </span>integers<span> that follow each other in order. They have a difference of 1 between every two numbers. In a set of </span>consecutive integers<span>, the mean and the median are equal. If n is an </span>integer, then n, n+1, and n+2 would be consecutive integers<span>. Examples.</span>
There are a couple of operations you can do on powers
We can multiply powers with the same base
x4⋅x2=(x⋅x⋅x⋅x)⋅(x⋅x)=x6
xa⋅xb=xa+b
This is an example of the product of powers property tells us that when you multiply powers with the same base you just have to add the exponents
