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s344n2d4d5 [400]
3 years ago
8

4x squared + 16x + 15 (Factoring I need help understanding)

Mathematics
1 answer:
Readme [11.4K]3 years ago
8 0
The answer is (2x+3)(2x+5)

using the FOIL method

first: (2x)(2x)
outside: (2x)(5)
inside:(3)(2x)
last:(3)(5)

4x^2+10x+6x+15

collect like terms

4x^2+16x+15
You might be interested in
Which statement is true of normally distributed data ??
balandron [24]

Answer:

The correct option is b. approximately 68% of the data falls within 1 standard deviation (+-1) of the mean

Explanation:

According to the empirical rule of normal distribution:

1. Approximately 68% of the data falls within 1 standard deviation \pm 1 of the mean

2. Approximately 95% of the data falls within 2 standard deviations \pm 2 of the mean

3. Approximately 99.7% of the data falls within 3 standard deviations \pm 3 of the mean.

Therefore, among the given options, only option b adheres to the empirical rule of the normal distribution. Therefore, the option b is correct


8 0
3 years ago
Determine if the two triangles are similar if so state the similarity statement and state the reason?
serg [7]
I know they are but i’m not sure why.
8 0
3 years ago
In a survey of US adults, twenty percent say they never exercise. This is the highest level seen in five years.
Andrews [41]

Answer:

0.20 - 1.96\sqrt{\frac{0.2(1-0.2)}{1000}}=0.175

0.20 + 1.96\sqrt{\frac{0.2(1-0.2)}{1000}}=0.225

The 95% confidence interval would be given by (0.175;0.225)

Step-by-step explanation:

Assuming this question: In a survey of 1000 US adults, twenty percent say they never exercise. This is the highest level seen in five years.1 Find a 95% confidence interval for the proportion of US adults who say they never exercise. Round your answers to three decimal places.

Previous concepts

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".  

The margin of error is the range of values below and above the sample statistic in a confidence interval.  

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".  

The population proportion have the following distribution

p \sim N(p,\sqrt{\frac{p(1-p)}{n}})

Solution to the problem

In order to find the critical value we need to take in count that we are finding the interval for a proportion, so on this case we need to use the z distribution. Since our interval is at 95% of confidence, our significance level would be given by \alpha=1-0.95=0.05 and \alpha/2 =0.025. And the critical value would be given by:

z_{\alpha/2}=-1.96, z_{1-\alpha/2}=1.96

The confidence interval for the mean is given by the following formula:  

\hat p \pm z_{\alpha/2}\sqrt{\frac{\hat p (1-\hat p)}{n}}

If we replace the values obtained we got:

0.20 - 1.96\sqrt{\frac{0.2(1-0.2)}{1000}}=0.175

0.20 + 1.96\sqrt{\frac{0.2(1-0.2)}{1000}}=0.225

The 95% confidence interval would be given by (0.175;0.225)

6 0
3 years ago
Help with algebraic equation and to solve it plz
lutik1710 [3]
4) fifteen less than y is 32

15 - y= 32

15 - (-17)= 32

two negatives become positive so 15+17= 32


7 0
4 years ago
Leo is purchasing a bike that is on sale for 30% off. He knows the function that represents the sale price of his bike is c(p) =
Umnica [9.8K]

Answer:

f[c(p)] = 0.784p

Step-by-step explanation:

sales discount = 30%

sales tax = 12%

c(p) = 0.7p where p is the original price

f(c) = 1.12c where c is the sales price of the bike.

f[c(p)] = 1.12(0.7p)

f[c(p)] = 0.784p    Last option.

Assume: p = 100

c(100) = 0.7(100) = 70

f(70) = 1.12(70) = 78.4

f[70(100)] = 0.784(100) = 78.4

7 0
3 years ago
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