My sister has 200 saved text messages of these 24 from her brother. What percent of the total text are from her brother.
1 answer:
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Answer:
The correct options are;
1) ΔBCD is similar to ΔBSR
2) BR/RD = BS/SC
3) (BR)(SC) = (RD)(BS)
Step-by-step explanation:
1) Given that RS is parallel to DC, we have;
∠BDC = ∠BRS (Angles on the same side of transversal)
Similarly;
∠BCD = ∠BSR (Angles on the same side of transversal)
∠CBD = ∠CBD = (Reflexive property)
Therefore;
ΔBCD ~ ΔBSR Angle, Angle Angle (AAA) rule of congruency
2) Whereby ΔBCD ~ ΔBSR, we therefore have;
BC/BS = BD/BR → (BS + SC)/BS = (BR + RD)/BR = 1 + SC/BS = RD/BR + 1
1 + SC/BS = 1 + RD/BR = SC/BS = 1 + BR/RD - 1
SC/BS = RD/BR
Inverting both sides
BR/RD = BS/SC
3) From BR/RD = BS/SC the above we have by cross multiplication;
BR/RD = BS/SC gives;
BR × SC = RD × BR → (BR)(SC) = (RD)(BR).
Answer:
Please find attached, the required graph created on MS Excel
Step-by-step explanation:
The distance between Sandy's house and the school = 200 m
The number of minutes Sandy talked to her friend for = 10 minutes
The time it took Sandy to return home to pick her homework = 5 minutes
Let <em>x </em>represent Sandy's location she stops to talk to her friend 10 minutes, we have;
The slope of the motion on the graph, m₁ = (x - 0)/(t - 0)
The slope of her motion running home to pick the up her homework, m₂ = (x - 0)/(5 - 0)
Given that t > 5, the slope on trip back home, m₁, is larger than are her initial slope, m₂
Therefore, where x = 125, we have;
The rate at which she returned home = m₂ = (125 m - 0)/(5 min - 0) = 25 m/min
Given that the same rate m₂ is what she used in heading back to school, we have;
The time it takes her to get to school = 200 m/(25 m/min) = 8 minutes
Therefore, whereby it took her 10 minutes to reach point <em>x</em>, we have the following coordinate points on the graph in a tabular form;
The plot of the above point is completed using MS Excel as shown in the attached diagram.
