Answer:
A. 384.16
B. 2,401
C. 9,604
D. No
Step-by-step explanation:
Calculation to determine how large a sample should be taken for each desired margin of error
First step is to find σ which represent Population Standard deviation
σ=($50,000-$30,000)/4
σ=$20,000/4
σ = 5,000
Now let calculate how large a sample should be taken for each desired margin of error
Using this formula
n = (Za/2*σ/E)^2
Where,
Za/2=1-0.95/2
Za/2=0.05/2
Za/2=0.025
Z-score 0.025=1.96
Za/2=1.96
σ =5,000
E represent Desired margin of error
Let plug in the formula
a. $500
n = (1.96* 5,000/$500)^2
n=(9,800/$500)^2
n=(19.6)^2
n = 384.16
b. $200
n = (1.96*5,000/200)^2
n=(9,800/$200)^2
n=(49)^2
n = 2,401
c. $100
n = (1.96*5,000/$100)^2
n=(9,800/$100)^2
n=(98)^2
n = 9,604
Therefore how large a sample should be taken for each desired margin of error will be :
A. $500= 384.16
B. $200= 2,401
C. $100= 9,604
d.NO, Based on the information calculation i would NOT recommend trying to obtain the $100 margin of error reason been that it is highly costly compare to $500 margin of error and $200 margin of error.
Answer:
Ok, we know that the width of the door is 4.20m.
Then, if the arc is at the top of the door, we will have that the diameter of that "half circle" will be equal to the width of the door.
Then the diameter of the arc is 4.20m
And the radius is defined as half of the diameter, so we have:
radius = 4.20m/2 = 2.10m
And we can write this in cm (because the probelm ask for it)
1m = 100cm
then 2.10m = 2.1*100cm = 210cm
Now, we know that the perimeter of a circle is:
P = 2*pi*r
where pi = 3.14
Then the perimeter (or arc) of half a circle will be half of that:
Arc = (2*pi*r)/2 = pi*r
and r = 210cm, pi = 3.14
Arc = 3.14*210cm = 659.4cm
Probably uncomfortable,,,,
The common factor is b since it is divisible by both 2b and 5b
The correct answer is f=(1/3)m
