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natali 33 [55]
3 years ago
11

Solve the quadratic equation by completing the square.

Mathematics
1 answer:
vampirchik [111]3 years ago
7 0

Answer:

x = -4.59, -7.41.

Step-by-step explanation:

x^2 + 12x + 34 = 0

(x + 6)^2 - 36 +34 = 0

(x + 6)^2 = 36 - 34 = 2

x + 6 = +/-√2

x =   +/-√2 - 6

x = -4.59, -7.41

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Vinil7 [7]

Answer:

5.25 cm

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1) (x - 2)/(x - 3) + (3x - 11)/(x - 4) = (4x + 13)/(x + 1)​
mote1985 [20]

Step-by-step explanation:

or,(x-2)(x-4)+(3x-11)(x-3)/(x-3)(x-4)=(4x+13)/(x+1)

or,x^2-4x-2x+8+3x^2-9x-11x+33/x^2-4x-3x+12=(4x+13)/(x+1)

or,4x^2-4x-2x-9x-11x+8+33/x^2-7x+12=(4x+13)/(x+1)

or,4x^2-26x+41/x^2-7x+12=(4x+13)/(x+1)

or, (x+1)(4x^2-26x+41)=(4x+13)(x^2-7x+12)

or,4x^3-26x^2+41x+4x^2-26x+41=4x^3-28x^2+48x+13x^2-91x+156

or,-26x^2+4x^2+28x^2-13x^2+41x-26x-48x+91x=156-41

or,-7x^2+58x=115

or,-7x^2+58x-115=0

or,-(7x^2-58x+115)=0

or,7x^2-58x+115=0

or,7x^2-(35+23)x+115=0

or,7x^2-35x-23x+115=0

or,7x (x-5)-23 (x-5)=0

or, (x-5)(7x-23)=0

Either, Or,

(x-5)=0 (7x-23)=0

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:x=5 :x=23/7

Hence,x=5 or 23/7

7 0
2 years ago
Calcular: E = (sec245o + tg45o) ctg37o - 2cos60o
Vlada [557]

Answer:

-2.813

Step-by-step explanation:

Se simplifica inicialmente la fórmula en términos de las funciones trigonométricas fundamentales (Initially, the formula is simplified in terms of fundamental trigonometric functions):

(\sec 245^{\circ} + \tan 45^{\circ} )\cdot \cot 37^{\circ} - 2\cos 60^{\circ}

\left(\frac{1}{\cos 245^{\circ}}+\frac{\sin 45^{\circ}}{\cos 45^{\circ}}  \right)\cdot \left(\frac{\cos 37^{\circ}}{\sin 37^{\circ}} \right) - 2\cdot \cos 60^{\circ}

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-2.813

7 0
3 years ago
Continue the following pattern; describe the eighth figure in this pattern
Bumek [7]
The correct answer would be C. Hope that helps.
5 0
3 years ago
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Hope this helps!=)

3 0
3 years ago
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