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iren [92.7K]
4 years ago
6

If a+bi is a zero of a function and the coefficients of the polynomial are real, what will be the other complex zero of the func

tion?
1. -a + bi

2. a - bi

3. -a - bi

4. a
Mathematics
1 answer:
Mekhanik [1.2K]4 years ago
8 0
The conjugate of a binomial is simply the same binomial with a different sign in the middle, so the conjugate of x + y, is just x - y, and the conjugate of w - z is just w + z and so on.

now, complex roots never come all by their lonesome, her sister, the conjugate, is always along with her, so if the root a + bi is there, then her sister a - bi is also there too.
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Answer:

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Step-by-step explanation:

We are given the following information in the question:

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The volume is decreasing at a constant rate.

\displaystyle\frac{dV}{dt} = -948\text{ cubic inch per second}

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We have to find the rate of change of height with respect to time.

Volume of cone =

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525 = \displaystyle\frac{1}{3}\pi r^2h = \frac{1}{3}\pi (99)^2h\\\\\text{Instant heigth} = h = \frac{525\times 3}{\pi(99)^2}

Differentiating with respect to t,

\displaystyle\frac{dV}{dt} = \frac{1}{3}\pi \bigg(2r\frac{dr}{dt}h + r^2\frac{dh}{dt}\bigg)

Putting all the values, we get,

\displaystyle\frac{dV}{dt} = \frac{1}{3}\pi \bigg(2r\frac{dr}{dt}h + r^2\frac{dh}{dt}\bigg)\\\\-948 = \frac{1}{3}\pi\bigg(2(99)(-7)(\frac{525\times 3}{\pi(99)^2}) + (99)(99)\frac{dh}{dt}\bigg)\\\\\frac{-948\times 3}{\pi} + \frac{2\times 7\times 525\times 3}{99\times \pi} = (99)^2\frac{dh}{dt}\\\\\frac{1}{(99)^2}\bigg(\frac{-948\times 3}{\pi} + \frac{2\times 7\times 525\times 3}{99\times \pi}\bigg) = \frac{dh}{dt}\\\\\frac{dh}{dt} = -0.085131

Thus, the height of cone is decreasing at a rate of 0.085131 inch per second.

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