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pentagon [3]
3 years ago
13

What is the product of 9/14 and 7/15A. 1/10 B. 3/10C. 16/29D. 8/105​

Mathematics
2 answers:
Sedaia [141]3 years ago
6 0

Answer:

63/210 or 3/10

B.

Step-by-step explanation:

14 · 15 = 210

9 · 7 = 63

____ [38]3 years ago
3 0

Answer:

B- 3/10

Step-by-step explanation:

9/14 x 7/15

multiply across so you would now get 63/210 and we can divide the top and bottom by 21  so it will simplify to 3/10

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What are the like terms in the expression 8+x²-4x³+5x+2x²​
Virty [35]
X^2 and 2x^2 are alike.
They both have variables and the same exponent
4 0
3 years ago
An ounce is equal to about 28 g. If 1 g of soil contains 2.5 billion bacteria, how many bacteria are in 1 oz of soil?
Nimfa-mama [501]

Answer:

About 700 billion bacteria

Step-by-step explanation:

Given

1oz \approx 28g

1g = 25\ billion\ bacteria

Required

Number of bacteria in 1 oz

1g = 25\ billion\ bacteria

Multiply both sides by 28

28 * 1g = 25\ billion\ bacteria * 28

28g = 700\ billion\ bacteria

Recall that

1oz \approx 28g

This means:

1oz \approx 700\ billion\ bacteria

5 0
3 years ago
In each of Problems 5 through 10, verify that each given function is a solution of the differential equation.
WARRIOR [948]

Answer:

For First Solution: y_1(t)=e^t

y_1(t)=e^t is the solution of equation y''-y=0.

For 2nd Solution:y_2(t)=cosht

y_2(t)=cosht  is the solution of equation y''-y=0.

Step-by-step explanation:

For First Solution: y_1(t)=e^t

In order to prove whether it is a solution or not we have to put it into the equation and check. For this we have to take derivatives.

y_1(t)=e^t

First order derivative:

y'_1(t)=e^t

2nd order Derivative:

y''_1(t)=e^t

Put Them in equation y''-y=0

e^t-e^t=0

0=0

Hence y_1(t)=e^t is the solution of equation y''-y=0.

For 2nd Solution:

y_2(t)=cosht

In order to prove whether it is a solution or not we have to put it into the equation and check. For this we have to take derivatives.

y_2(t)=cosht

First order derivative:

y'_2(t)=sinht

2nd order Derivative:

y''_2(t)=cosht

Put Them in equation y''-y=0

cosht-cosht=0

0=0

Hence y_2(t)=cosht  is the solution of equation y''-y=0.

3 0
3 years ago
EXPLAIN PLEASE!!
Anestetic [448]
It’s 28 because if 2 + 2 = your adopted then it’s 28
6 0
3 years ago
Read 2 more answers
1. standard position ​
konstantin123 [22]

Answer:

An angle is in standard position if its vertex is located at the origin and one ray is on the positive x-axis.  

Step-by-step explanation:

The ray on the x-axis is called the initial side and the other ray is called the terminal side.

3 0
3 years ago
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