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Neko [114]
3 years ago
10

Samuel has 52 marbles in a bag. Fourteen are red, 13 are green and 25 are blue. If a marble is chosen at random, what is the pro

bability that it is green?
Mathematics
1 answer:
lorasvet [3.4K]3 years ago
7 0
.25
you can come to this conclusion by calculating 13/52
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Please help me I’m so lost
Snezhnost [94]

Answer:

You do 26 times 30 and then divide it by 2

3 0
3 years ago
Read 2 more answers
PLEASE HELP <br> Match each expression to the scenario it represents
joja [24]

Answer:

i)

0.79m

ii)

1.21m

iii)

7/5m

iv)

3/5m

Step-by-step explanation:

i)

The price of a USB memory stick selling at a 21% discount off its marked price (m)

The marked price m represents 100% of the value of the USB memory stick. Offering a 21% discount off the marked price will mean that the USB will be selling at;

(100 - 21)% of the marked price m

=79% of m

= (79/100)*m

= 0.79m

ii)

The price of a CD that sells for 21% more than the amount (m) needed to manufacture the CD.

The amount (m) needed to manufacture the CD would represent 100% of the value of the CD. Selling the CD for 21% more than the amount (m) needed to manufacture the CD will imply that the selling price is;

(100+21)% of m

= 121% of m

= (121/100)*m

= 1.21m

iii)

The final value of a painting after its initial value, m, increases by 2/5.

The initial value of the painting is given as m. The value of the painting is said to increase by 2/5 which means that the increase in its value would be;

2/5 of m

=2/5 * m

=2/5m

The final value of the painting will thus be;

initial value + increase in value

=m + 2/5m

= m(1+2/5)

=7/5m

iv)

The total number of markers that Nancy has if she gives away 2/5 of her m markers to Amy.

Initially, Nancy had a total of m markers. By giving away 2/5 of her markers to Amy, her markers reduced by;

2/5 of m

=2/5*m

=2/5m

The new number of her markers will be given by;

initial numbers - total given to Amy

= m - (2/5m)

= m(1 - 2/5)

=m(3/5)

=3/5m

5 0
3 years ago
consider the expression (2m + n - 5) and (-3 - 5m + 6n) what is the sum of the expression for n = -3 and m =6​
Mademuasel [1]

Answer:

Need more info

Is this supposed to be two different sums for each expression in each sets of ()

or are they together? like is each set multiplied together?

4 0
3 years ago
Please help me!!!!!​
denpristay [2]

Answer:  see proof below

<u>Step-by-step explanation:</u>

Given: A + B + C = π               → A = π - (B + C)

                                               → B = π - (A + C)

                                               → C = π - (A + B)

Use Sum to Product Identity: sin A - sin B = 2 cos [(A + B)/2] · sin [(A - B)/2]

Use the following Cofunction Identity: cos (π/2 - A) = sin A

<u>Proof LHS → RHS:</u>

LHS:                        sin A - sin B + sin C

                             = (sin A - sin B) + sin C

\text{Sum to Product:}\quad 2\cos \bigg(\dfrac{A+B}{2}\bigg)\cdot \sin \bigg(\dfrac{A-B}{2}\bigg)+2\cos \bigg(\dfrac{C}2{}\bigg)\cdot \sin \bigg(\dfrac{C}{2}\bigg)

\text{Given:}\qquad 2\cos \bigg(\dfrac{\pi -(B+C)}{2}+\dfrac{B}{2}}\bigg)\cdot \sin \bigg(\dfrac{A-B}{2}\bigg)+2\cos \bigg(\dfrac{C}2{}\bigg)\cdot \sin \bigg(\dfrac{C}{2}\bigg)\\\\\\.\qquad \qquad =2\cos \bigg(\dfrac{\pi -C}{2}\bigg)\cdot \sin \bigg(\dfrac{A-B}{2}\bigg)+2\cos \bigg(\dfrac{C}2{}\bigg)\cdot \sin \bigg(\dfrac{C}{2}\bigg)

.\qquad \qquad =2\cos \bigg(\dfrac{\pi}{2} -\dfrac{C}{2}\bigg)\cdot \sin \bigg(\dfrac{A-B}{2}\bigg)+2\cos \bigg(\dfrac{C}2{}\bigg)\cdot \sin \bigg(\dfrac{C}{2}\bigg)

\text{Cofunction:} \qquad 2\sin \bigg(\dfrac{C}{2}\bigg)\cdot \sin \bigg(\dfrac{A-B}{2}\bigg)+2\cos \bigg(\dfrac{C}2{}\bigg)\cdot \sin \bigg(\dfrac{C}{2}\bigg)

\text{Factor:}\qquad 2\sin \bigg(\dfrac{C}{2}\bigg)\bigg[ \sin \bigg(\dfrac{A-B}{2}\bigg)+\cos \bigg(\dfrac{C}{2}\bigg)\bigg]

\text{Given:}\qquad 2\sin \bigg(\dfrac{C}{2}\bigg)\bigg[ \sin \bigg(\dfrac{A-B}{2}\bigg)+\cos \bigg(\dfrac{\pi -(A+B)}{2}\bigg)\bigg]\\\\\\.\qquad \qquad =2\sin \bigg(\dfrac{C}{2}\bigg)\bigg[ \sin \bigg(\dfrac{A-B}{2}\bigg)+\cos \bigg(\dfrac{\pi}{2} -\dfrac{(A+B)}{2}\bigg)\bigg]

\text{Cofunction:}\qquad 2\sin \bigg(\dfrac{C}{2}\bigg)\bigg[ \sin \bigg(\dfrac{A-B}{2}\bigg)+\sin \bigg(\dfrac{A+B}{2}\bigg)\bigg]

\text{Sum to Product:}\qquad 2\sin \bigg(\dfrac{C}{2}\bigg)\bigg[ 2\sin \bigg(\dfrac{A}{2}\bigg)\cdot \cos \bigg(\dfrac{B}{2}\bigg)\bigg]\\\\\\.\qquad \qquad \qquad \qquad =4\sin \bigg(\dfrac{A}{2}\bigg)\cdot \cos \bigg(\dfrac{B}{2}\bigg)\cdot \sin \bigg(\dfrac{C}{2}\bigg)

\text{LHS = RHS:}\quad 4\sin \bigg(\dfrac{A}{2}\bigg)\cdot \cos \bigg(\dfrac{B}{2}\bigg)\cdot \sin \bigg(\dfrac{C}{2}\bigg)=4\sin \bigg(\dfrac{A}{2}\bigg)\cdot \cos \bigg(\dfrac{B}{2}\bigg)\cdot \sin \bigg(\dfrac{C}{2}\bigg)\quad \checkmark

6 0
3 years ago
12 spheres of the same size are made from melting a solid cylinder of 1 cm diameter and 2 cm height. Find the diameter of each s
mars1129 [50]

The answer is: The diameter is 4 centimeters.

The explanation  is shown below:

1. The volume of the cylinder is:

Vc=r^{2}h \pi

Where r is the radius (r=\frac{16cm}{2}=8cm) and h is the height (h=2cm).

Then:

Vc=(8cm)^{2}}(2cm)\pi\\Vc=128\pi

2. The total volume of the 12 spheres is:

Vs=12(\frac{4}{3}r^{3}\pi)\\Vs=16r^{3}\pi

3. The volume of the cylinder and the total volume of all the 12 spheres, are equal, therefore:

Vc=Vs\\128\pi=16r^{3}\pi

4. Now, you must solve for the radius:

r=\sqrt[3]{\frac{128\pi}{16\pi}}\\r=2cm

5. The diameter is:

d=2r\\d=2(2cm)\\d=4cm

5 0
3 years ago
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