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Tcecarenko [31]
2 years ago
8

What is the solution set for the equation (2x-1)(x+5)=0

Mathematics
2 answers:
Wewaii [24]2 years ago
8 0

I hope This Helps❣ If U Nees Help Notify Me And I Will Post More❣

satela [25.4K]2 years ago
4 0

Answer:

x = 1/2    x=-5

Step-by-step explanation:

(2x-1)(x+5)=0

Using the zero product property

2x-1 =0  x+5 =0

2x= 1    x = -5

x = 1/2    x=-5

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If BE=6.25 calculate EC
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Complete the solution of the equation. fine the value of y <br><br> 9x+7y=-12
dimaraw [331]

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8 0
2 years ago
Factor the quadratic expression in the equation y = 2x2 + 8x - 154 and find the zeros of the equation. Then
Tema [17]

Answer:

zeros: -11 , 7

Line of symmetry: x = -2

Step-by-step explanation:

y = 2x² + 8x - 154 = 2*(x² + 4x - 77) = 2*(x+11)(x-7)

y = 0

x = - 11 or x = 7

line of symmetry: x = 1/2 (-11 + 7) = -2

2x² + 8x - 154 = 2*(x² + 4x +4) - 162 = 2 * (x+2)² - 162

vertex (h , k): h = -2 , k = -162

Line of symmetry: x = -2

6 0
3 years ago
Factor completely:<br>64 - y^3
madam [21]
From your equation, you can see that you have a difference of two cubes (aka two cubes being subtracted): 64, which is 4^{3}, and y^{3}.

There is rule for the difference of two cubes:
The difference of two cubes is equal to the difference of the cube roots times a binomial, which is the sum of the squares of the roots plus the product of the roots.

That sounds pretty confusing, but it's much easier to understand when put mathematically. Let's say our two cubes are a^{3} and b^{3}. The difference of those two cubes is:
a^{3} - b^{3} = (a - b)( a^{2} + ab + b^{2})

In our problem, a = 4 (since a^{3} = 64) and b = y (since b^{3} = y^{3}. Plug these values into the rule to find the factor of 64 - y^3:
64 - y^3 \\&#10;= (4 - y)( 4^{2} + 4y + y^{2}) \\&#10;=  (4 - y)( 16 + 4y + y^{2})

-----

Answer: (4 - y)( 16 + 4y + y^{2})

8 0
2 years ago
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