Check out tiger algebra you can get an answer there good luck
Answer:
Step-by-step explanation:
So we would have to multiply the "2x - 8" by 5 each resulting in 10x - 40 + 15. Then we subtract which results in 10x - 25 = - 15. We add 25 to 25 and 15 resulting in 10x = 10. We divide each by 10 which results in x = 1.
If the sum of an integer and 6 times the next consecutive integer is 61, the the value of lesser integer is 7
Consider the first odd integer as x
Then the next consecutive odd integer = x+2
The 6 times the second integer= 6(x+2)
= 6x+12
Sum of an integer and 6 times the next consecutive odd integer is 61
Then the equation will be
x + 6x+12 = 61
Add the like terms in the equation
(1+6)x + 12 = 61
7x +12 = 61
Move 12 to the right hand side of the equation
7x = 61-12
7x = 49
x = 49/7
x = 7
The second number is
x+2 = 7+2
= 9
Hence, if the sum of an integer and 6 times the next consecutive integer is 61, the the value of lesser integer is 7
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That would be 9c+63 i’m pretty sure
36.772 is the answer to 58% of 63.4,so your answer would be....
