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Ilia_Sergeevich [38]
3 years ago
10

There were 20 gallons of gasoline in your car's gas tank. You used 4 gallons and 1 quart. How much gasoline remains in the tank?

Mathematics
1 answer:
iris [78.8K]3 years ago
4 0
There would be 26.75 gallons left in the tank cuz 4 quarters equals to one ggalllon
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MULTIPLE CHOICE HELP ASAP! Brainliest for correct answer.
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Answer:

An equation of the circle with centre (-2,1) and radius 3 is \mathbf{(x+2)^2+(x-1)^2=9}

Option D is correct.

Step-by-step explanation:

Looking at the figure we get centre of circle C (-2,1) and radius of circle r = 3

The equation of circle is of form: (x-h)^2+(x-k)^2=r^2 where (h,k) is centre and r is radius.

We have centre C (-2,1) so, we have h = -2 and k = 1

We have radius = 3 so, r = 3

Putting values in the equation and finding the required equation:

(x-h)^2+(x-k)^2=r^2\\(x-(-2))^2+(x-1)^2=(3)^2\\(x+2)^2+(x-1)^2=9

So,  an equation of the circle with centre (-2,1) and radius 3 is \mathbf{(x+2)^2+(x-1)^2=9}

Option D is correct.

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Find the equation of the graphed line.
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<h3><u>Answer:</u></h3>

\boxed{\boxed{\pink{\bf \leadsto Hence \ option\ [d]\ \bigg(y =  \dfrac{5}{2}x + 5\bigg) \ is \ correct  }}}

<h3><u>Step-by-step explanation:</u></h3>

Here from the given graph we can see that the graph the graph intersects x axis at (2,0) and y axis at (5,0). On seeing options it's clear that we have to use Slope intercept form . Which is :-

\large\boxed{\orange{\bf y = mx + c} }

We know that slope is \tan\theta. So here slope will be ,

\red{\implies slope = \tan\theta} \\\\\implies slope =\dfrac{PERPENDICULAR}{BASE} \\\\\bf \implies slope =\dfrac{5}{2}

Hence the slope is 5/2 . And here value of c will be 5 since it cuts y axis at (5,0).

\purple{\implies y = mx + c }\\\\\implies y = \dfrac{5}{2}x + 5 \\\\\underline{\boxed{\red{\tt \implies y = \dfrac{5}{2}x + 5 }}}

<h3><u>Hence</u><u> </u><u>option</u><u> </u><u>[</u><u> </u><u>d</u><u> </u><u>]</u><u> </u><u>is</u><u> </u><u>corre</u><u>ct</u><u> </u><u>.</u><u> </u></h3>
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9. A ball is thrown into the air at an initial velocity of 18 meters per second from an initial height of 10
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D3 secaonds answer 20 meters=1

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