If the coefficient of x^2 is negative, the graph will be n shaped and curve down instead of like a u shape if it was positive. If the vertex is below the x axis and curves down, it won’t pass the x axis, Tia is right.
Answer:
Her answer is wrong because she the object cannot hit the ground at negative seconds. She could’ve have used other methods because she used the quadratic formula. The advantages is that it works for every situation. The disadvantages is that it takes longer. She should’ve used a different method.
Step-by-step explanation:
Answer:
Step-by-step explanation:
b/c we know that these triangles both have equal sides... that is given that <u>ab</u> and<u> be</u> are the same length. and that <u>be </u>and <u>cd</u> are parallel , we know that they both are isosceles triangles and that the base angles are the same. The side on <u> ad </u>and<u> ae</u> have equal angles.
so we can make the equation
2a +56 = 180 (b/c we know that around a triangle it's 180°
2 a = 124
a = 62
so ∠ BAE = 62°
:)
0≤h(t)≤144, which means that the height of the object can be between 0 and 144 feet, including those limits.
Fractions less than 1/2 are 1/6 & 4/10.
Fractions greater than 1 are 5/4 & 15/12.
Fractions closer to 0 than to 1 are 1/8, 1/4, & 3/10.
