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sertanlavr [38]
3 years ago
10

On September 30, picture perfect physicians invested$100,000 in new medical equipment. What is the new assets, liabilities and e

quity
Mathematics
1 answer:
Serjik [45]3 years ago
3 0
The investment of $100,000 dollars in new medical equipment by the picture perfect physician would constitute as his asset. This would be classified as his non-current assets (equipment is<span> usually classified as non-current assets). If he purchased this on credit, this transaction would affect his liability since this would be a payable on his part. The equity would not change since this is not a transaction that would involve his equity. Assuming that this was a credit transaction, there would be an increase of $100,000 in asset and at the same time, there would be an increase in liability in the amount of $100,000.</span>
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nasty-shy [4]

Answer:

correct option is C)  2.8

Step-by-step explanation:

given data

string vibrates form =  8 loops

in water loop formed =  10 loops

solution

we consider  mass of stone = m

string length = l

frequency of tuning = f

volume = v

density of stone = \rho

case (1)  

when 8 loop form with 2 adjacent node is \frac{\lambda }{2}

so here

l = \frac{8 \lambda _1}{2}      ..............1

l = 4 \lambda_1\\\\\lambda_1 = \frac{l}{4}

and we know velocity is express as

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here tension = mg

so

\sqrt{\frac{mg}{\mu}}   =   f × \lambda_1     ..........................3

and

case (2)  

when 8 loop form with 2 adjacent node is \frac{\lambda }{2}

l = \frac{10 \lambda _1}{2}      ..............4

l = 5 \lambda_1\\\\\lambda_1 = \frac{l}{5}

when block is immersed

equilibrium  eq will be

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T + v × \rho × g = mg

and

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from equation 2

f × \lambda_2 = f  × \frac{1}{5}  

\sqrt{\frac{v\rho _{stone} g - v\rho _{water} g}{\mu}} = f \times \frac{1}{5}     .......................5

now we divide eq 5 by the eq 3

\sqrt{\frac{vg (\rho _{stone} - \rho _{water})}{\mu vg \times \rho _{stone}}} = \frac{fl}{5} \times \frac{4}{fl}

solve irt we get

1 - \frac{\rho _{stone}}{\rho _{water}}  = \frac{16}{25}

so

relative density \frac{\rho _{stone}}{\rho _{water}} = \frac{25}{9}

relative density = 2.78 ≈ 2.8

so correct option is C)  2.8

3 0
3 years ago
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sleet_krkn [62]

Answer:

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Step-by-step explanation:

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= 13/429 (by dividing both numbers by 7)
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Step-by-step explanation:

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