Step-by-step explanation:
The basic form of equation:
(x-h)²=4a(y-k),
(h,k)=coordinates of vertex
(h, k+a) = coordinate of focus
For given parabola:
axis of symmetry: x=2
(h, k) =(2,-3)
(h, k+a)=(2,5)
k+a=5
-3+a=5
a=8(distance from vertex to focus on the axis of symmetry)
equation: (x-2)²=4×8(y+3)
(x-2)²= 32(y+3)
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Answer:
h, j2, f, g, j1, i, k, l (ell)
Step-by-step explanation:
The horizontal asymptote is the constant term of the quotient of the numerator and denominator functions. Generally, it it is the coefficient of the ratio of the highest-degree terms (when they have the same degree). It is zero if the denominator has a higher degree (as for function f(x)).
We note there are two functions named j(x). The one appearing second from the top of the list we'll call j1(x); the one third from the bottom we'll call j2(x).
The horizontal asymptotes are ...
- h(x): 16x/(-4x) = -4
- j1(x): 2x^2/x^2 = 2
- i(x): 3x/x = 3
- l(x): 15x/(2x) = 7.5
- g(x): x^2/x^2 = 1
- j2(x): 3x^2/-x^2 = -3
- f(x): 0x^2/(12x^2) = 0
- k(x): 5x^2/x^2 = 5
So, the ordering least-to-greatest is ...
h (-4), j2 (-3), f (0), g (1), j1 (2), i (3), k (5), l (7.5)
To find the volume for a cube you need to do length x width x height. make sure you put it as cm3 because it’s volume. hope it helps?
