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Anton [14]
3 years ago
6

a worker in a silver mine descends 71 feet. Use an integer to represent the change in the workers position.

Mathematics
1 answer:
alexira [117]3 years ago
6 0

Answer:

iuyhgt

Step-by-step explanation:

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Solve log6 60 - log6 30
Mariana [72]

Answer:

log_a(b) - log_a(c) = log_a(\frac{b}{c})

Using that formula we get:

log_6(60) - log_6(30)  = log_6(2)

5 0
3 years ago
Explain in words,how to find the product of -4(-1.5) using a number line. Where do you end up?
Gemiola [76]

Answer:

so u multiply negative four times nagative 1.5

6 0
3 years ago
The volume of two similar solids are 128 m3
arsen [322]

Answer:

Solution given:

The volume of two similar solids are 128 m³

and 250 m³.

surface area of larger solid is 250m²

<u>let</u><u> </u><u>surface</u><u> </u><u>area</u><u> </u><u>of</u><u> </u><u>smaller</u><u> </u><u>solid</u><u> </u><u>be</u><u> </u><u>x</u><u>.</u>

<u>Since</u><u> </u><u>they</u><u> </u><u>are</u><u> </u><u>similar</u>

\frac{250}{128}   =  \frac{250}{x}

x=128

the surface are of the

smaller solid is 128m²

8 0
3 years ago
What is the value of x?
andrey2020 [161]

Since this is a parallelogram and the angles are adjacent to one another, a theorem will prove that the sum of these two angles would equal 180°

Therefore, we can set up this equation:

(2x + 24) + x = 180 ⇒ Remove parentheses

2x + 24 + x = 180 ⇒ Combine like terms

3x + 24 = 180 ⇒ Subtract 24 from both sides

3x = 156 ⇒ Divide both sides by 3

x = 52°


3 0
2 years ago
Read 2 more answers
Verify that [tan(theta) + cot(theta)]^2 = sec^2(theta) + csc^2(theta)
Wittaler [7]

(tanθ + cotθ)² = sec²θ + csc²θ

<u>Expand left side</u>: tan²θ + 2tanθcotθ + cot²θ

<u>Evaluate middle term</u>: 2tanθcotθ = 2*\frac{sin\theta}{cos\theta}*\frac{cos\theta}{sin\theta} = 2

⇒ tan²θ + 2+ cot²θ

= tan²θ + 1 + 1 + cot²θ

<u>Apply trig identity:</u>  tan²θ + 1 = sec²θ

⇒ sec²θ + 1 + cot²θ

<u>Apply trig identity:</u>  1 + cot²θ = csc²θ

⇒ sec²θ + csc²θ

Left side equals Right side so equation is verified


7 0
2 years ago
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