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Anton [14]
3 years ago
6

a worker in a silver mine descends 71 feet. Use an integer to represent the change in the workers position.

Mathematics
1 answer:
alexira [117]3 years ago
6 0

Answer:

iuyhgt

Step-by-step explanation:

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Write a polynomial that has a GCF of 7m and another with a GCF of 2ab squared.
SVEN [57.7K]

The polynomial that has a GCF of 7m is 14mn - 21m + 49m²n + 7mn²

The polynomial that has a GCF of 2ab² is 6a²b² - 8ab³ + 4a³b² + 2a³b³

<h3>Writing Polynomials </h3>

From the question, we are to write a polynomial that has a GCF of 7m

That is,

We are to write a polynomial that has a greatest common factor of 7m

<em>Writing the polynomial</em>

14mn - 21m + 49m²n + 7mn²

The  polynomial above has a greatest common factor of 7m. That is, 7m is the greatest factor that can divide each of the terms

We are to write a polynomial with a GCF of 2ab²

<em />

<em>Writing the polynomial</em>

6a²b² - 8ab³ + 4a³b² + 2a³b³

The polynomial above has a greatest common factor of 2ab². That is, 2ab² is the greatest factor that can divide each of the terms

Hence,

The polynomial that has a GCF of 7m is 14mn - 21m + 49m²n + 7mn²

The polynomial that has a GCF of 2ab² is 6a²b² - 8ab³ + 4a³b² + 2a³b³

Learn more on Writing polynomials here: brainly.com/question/4525973

#SPJ1

7 0
1 year ago
Write 4km^2/12k in simplest form
Slav-nsk [51]

4km^2/12k in simplest form is 1/3y^2

3 0
3 years ago
CAN SOMEONE PLEASE HELP!! I DONT UNDERSTAND. i WILL GIVE BRAINLIEST!!!!
HACTEHA [7]

Answer:

u should give me the formula for ur question cuz I kind of understand but I did it years ago

7 0
2 years ago
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How would i solvd this problem as sn improper fraction 2 1/8
zmey [24]
17/8..........................................
7 0
3 years ago
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If cosθ=2/3 find cscθ using identities. This is in quad. 1.
laiz [17]

Step-by-step explanation:

  • cos θ = 2/3

\quad \twoheadrightarrow\sf {cos \; \theta = \dfrac{Base}{Hypotenuse} } \\

Hence, base = 2 units and hypotenuse = 3 units.

\quad \twoheadrightarrow\sf { H^2 = B^2 + P^2} \\

\quad \twoheadrightarrow\sf { P^2 = H^2 - B^2} \\

\quad \twoheadrightarrow\sf { P^2 = (3)^2 - (2)^2} \\

\quad \twoheadrightarrow\sf { P^2 = 9- 4} \\

\quad \twoheadrightarrow\bf { P = \sqrt{5}} \\

Now, we know that :

\quad \twoheadrightarrow\sf {cosec \; \theta = \dfrac{Hypotenuse}{Perpendicular} } \\

\quad \twoheadrightarrow\bf{cosec \; \theta = \dfrac{3}{\sqrt{5}} } \\

Therefore, the required answer is 3/√5.

4 0
2 years ago
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