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3 years ago

a worker in a silver mine descends 71 feet. Use an integer to represent the change in the workers position.

Mathematics

1 answer:

alexira [117]3 years ago

6 0

Answer:

iuyhgt

Step-by-step explanation:

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Graph the relation. Is the relation a function? Why or why not? {(–1, 1), (–2, 1), (–2, 2), (0, 2)} Yes; there is only one domai

Luden [163]

{(–1, 1), (–2, 1), (–2, 2), (0, 2)}

In a function, each input has an output

Each domain has a range. In a function, range can be repeated but domain cannot be repeated. Same domain cannot have two range values.

Here domain is {-1, -2, -2, 0}

Range is { 1, 1, 2, 2}

Domain -2 is repeating so this relation is not a function

Answer : No; a domain value has two range values.

7 0

2 years ago

The score on a trivia game is obtained by subtracting the number of incorrect answer from twice the number of correct answer. If

brilliants [131]

Answer:

The player answer correctly 30 questions

Step-by-step explanation:

First we have to develop the information that gives us as 2 equations

x = correct answer

y = incorrect answer

z = score = 40

h = total answer = 50

2x - y = z x + y = h

2x - y = 40 x + y = 50

we clear the x of one equation and replace the value of x in the other equation

x = 50 - y

2x - y = 40

2(50 - y) - y = 40

100 - 2y - y = 40

-3y = 40 -100

y = -60/-3

y = 20

x = 50 - y

x = 50 - 20

x = 30

3 0

3 years ago

Find the area of the shaded region.f(x)=4x+3x2−x3,g(x)=0<br> The area is _____.

Tasya [4]

Answer:

The answer is " $\bold{\frac{7}{2}}$ "

Step-by-step explanation:

Given value:

$\to f(x)=4x+3x^2-x^3\\\\\to g(x)=0$

Find:

area=?

calculation:

$\ Area = \int_{-1}^{0} -(4x+3x^2-x^3) dx + \int_{0}^{1} (4x+3x^2-x^3) dx \\\\$

$= -(2x^2+x^3- \frac{x^4}{4})_{-1}^{0} + (2x^2+x^3- \frac{x^4}{4})_{0}^{1}\\\\\\= -( 2x^2+x^3- \frac{x^4}{4})_{-1}^{0} + (2x^2+x^3- \frac{x^4}{4})_{0}^{1}\\\\\\= ( 2- 1 -\frac{1}{4}) + (2+1- \frac{1}{4})\\\\\\= ( \frac{8-4-1}{4}) + (\frac{8+4-1}{4})\\\\= ( \frac{3}{4}) + (\frac{11}{4})\\\\= \frac{3}{4} + \frac{11}{4}\\\\= \frac{11+3}{4}\\\\= \frac{14}{4}\\\\= \frac{7}{2}\\\\$