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ValentinkaMS [17]
4 years ago
14

Manny is playing a game. He has -300 points. He earns 245 points. What is his score?

Mathematics
2 answers:
aleksandrvk [35]4 years ago
7 0

Answer:

-55

Step-by-step explanation:

Jet001 [13]4 years ago
5 0

Answer:-55

Step-by-step explanation:-300 + 245 = -55

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A zoo has 15 toucans and 60 parrtos
Nimfa-mama [501]

Answer:

It has 75 birds

Step-by-step explanation:

Hope that's the answer since I can't get the question

6 0
3 years ago
What is the value of 5/6÷3/7
weqwewe [10]
<span>1)
5/6 - fraction
</span><span>3/7 -  fraction
(5/6)÷(3/7)=(5*7)/(6*3)=35/18=1 </span>\frac{17}{18}
<span>2) 
</span><span>5/6÷3/7=5/6/3/7=5/126</span><span>

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7 0
3 years ago
How can a line segment CD be written using symbols?
kykrilka [37]

Solution

- The line segment CD is written as follows:

\overline{CD}

6 0
2 years ago
<img src="https://tex.z-dn.net/?f=%20%5Csqrt%7B%20-%2064%7D%20" id="TexFormula1" title=" \sqrt{ - 64} " alt=" \sqrt{ - 64} " ali
LenKa [72]

Answer:

<h3>8i</h3>

Step-by-step explanation:

4 0
3 years ago
Please help me !!!!!!!!!!
maria [59]

Answer:

EF=6

Step-by-step explanation:

In this problem, one is given a circle with two secants (that is a line that intersects a circle at two points). One is given certain measurements, the problem asks one to find the unknown measurements.

The product of the lengths theorem gives a ratio between the lengths in the secants. Call the part of the secant that is inside the circle (inside), and the part of the secant between the exterior of the circle and the point of intersection of the secants (outside). The sum of (inside) and (outside) make up the entire secant, call this measurement (total). Remember, there are two secants, (secant_1) and (secant_2) in this situation. With these naming in mind, one can state the product of the length ratio as the following:

\frac{total_1}{outside_2}=\frac{total_2}{outside_1}

Alternatively, one can state it like the following ratio:

\frac{inside_1+ouside_1}{outside_2}=\frac{inside_2+outside_2}{outside_1}

Apply this ratio to the given problem, substitute the lengths of the sides of the secants in and solve for the unknown.

\frac{EF+FG}{HG}=\frac{SH+HG}{FG}

\frac{2x+4}{5}=\frac{x+5}{4}

Cross products, multiply the numerator and denominators of opposite sides of the fraction together,

\frac{2x+4}{5}=\frac{x+5}{4}

4(2x+4)=5(x+5)

Simplify,

4(2x+4)=5(x+5)

8x+16=5x+25

Inverse operations,

8x+16=5x+25

3x+16=25\\3x=9\\x=3

Substitute this value into the equation given for the measure of (EF),

EF=2x\\x=3\\\\EF=2x\\=2(3)\\=6

6 0
3 years ago
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