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kondor19780726 [428]
3 years ago
9

the volume of a prism with equilateral triangular cross-section is 270cm^3 . If the length if the prism is 10 root 3 cm, what is

the length of the side of the equilateral triangular cross-section ?​
Mathematics
1 answer:
stepan [7]3 years ago
5 0

Given:

The volume of a prism with equilateral triangular cross-section is 270cm³.

Length of the prism = 10\sqrt{3} cm

To find:

The length of the side of the equilateral triangular cross-section.

Solution:

Formulae used:

Area of an equilateral triangle is

Area=\dfrac{\sqrt{3}}{4}a^2

Where a is the side length of equilateral triangle.

Volume of prism is

V=Bh

Where, B is base area and h is the height of the triangular prism.

Cross section of the prism is an equilateral triangular so the base area of the prism is  \dfrac{\sqrt{3}}{4}a^2 sq. cm.

The volume of the prism is

V=\dfrac{\sqrt{3}}{4}a^2\times 10\sqrt{3}

270=\dfrac{10(3)}{4}a^2

270=\dfrac{30}{4}a^2

270=7.5a^2

Divide both sides by 7.5.

\dfrac{270}{7.5}=a^2

36=a^2

\pm \sqrt{36}=a

6=a

It takes only positive value because the side cannot be negative.

Therefore, the length of the side of the equilateral triangular cross-section is 6 cm.

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\bf \cfrac{300 ft}{2.29 s}\cdot \cfrac{3600 s}{hr}\cdot \cfrac{mi}{5280 ft}~\hspace{10em}\stackrel{\textit{using minutes as well}}{\cfrac{300 ft}{2.29 s}\cdot \cfrac{60 min}{hr}\cdot \cfrac{60 s}{min}\cdot \cfrac{mi}{5280 ft}}

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What is the slope of the tangent line to the parametric curve x = t2 + 2t, y = t2 + 1 at t = 1?
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A road is made in such a way that the center of the road is higher off the ground than the sides of the road, in order to allow
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The maximum height of the road which is made in such a way that the center of the road is higher off the ground than the sides of the road is 16 feet.

<h3>What is the maxima of parabola?</h3>

The maxima of a parabola is where, it opens down its vertex at the maximum point in a coordinate graph. By equating the derivative of equation of parabola equal to zero, it can be found out.

A road is made in such a way that the center of the road is higher off the ground than the sides of the road, in order to allow rainwater to drain.

A cross-section of the road can be represented on a graph using the function,

f(x) = (x - 16)(x+ 16),

Here,<em> x </em>represents the distance from the center of the road, in feet.

This equation can be written as,

f(x) = (x - 16)^2

Now to find the maximum height, find the derivative of the above function as,

f(x) = (x - 16)^2\\f'(x) = (x - 16)^2\\f'(x)=2(x-16)(1)\\f'(x)=2(x-16)


Equate the above equation to zero as,

0=2(x-16)\\0=x-16\\x=16

Thus, the maximum height of the road which is made in such a way that the center of the road is higher off the ground than the sides of the road is 16 feet.

Learn more about the maxima of parabola here;

brainly.com/question/5399857

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Plz help me someone I am stuck I need the answer please and thank you so much
olga nikolaevna [1]

X= -3B + 2A

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comparing the corresponding elements,

X= [ 9+8 21-2]

-21+10 -3+4

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