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hram777 [196]
3 years ago
14

M^2/n^2 is equivalent to _____.

Mathematics
2 answers:
timurjin [86]3 years ago
8 0

Answer:

The correct answer to this would be C. m^2n-^2.



Stella [2.4K]3 years ago
3 0

As n is in the denominator and u r bringing it to numerator the exponent gains a negative , hence answer is C

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Find the value of c that makes t^2– 22t+ c a perfect square trinomial.
riadik2000 [5.3K]

Answer:

ZkgJHhHJ HHha sorry i am not sure

3 0
3 years ago
By rounding to one significant figure estimate 798/8*41
SpyIntel [72]

Answer:

Step 1: 798/ 8= 99.75

Step 2: 99.75 * 41 = 4089.75

The first significant figure is the first non-zero digit in a number. Therefore the first significant figure in 4089.75 is 4.

If the number following the value that you are rounding to (in this case, the first significant figure ie 4) is greater than or equal to 5, round up the value, ie add 1 to the number. Otherwise round down to the nearest whole number.

Since the number following the significant digit, 4, is zero we therefore round down the number.

Resulting in:

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Therefore, your answer is 4000

5 0
3 years ago
This isn't a question, just a tip!
masya89 [10]
Aww thank you. Im pretty sure you helped people cause you helped me :) I hope you have an amazing day!
3 0
3 years ago
Find the image of the given point
Ira Lisetskai [31]

Answer:

P' = (2, -6)

Step-by-step explanation:

In this translation, you just need to substitute x and y into the given translation to find what P' is. (x is -6 since it's the x-value of P, and y is -2 since it's the y-value of P):

where T(x, y) = (x + 8, y - 4) and x = -6 and y = -2,

T(-6, -2) = ((-6) + 8), (-2) - 4) (substitute x and y into the translation)

T(-6, -2) = (2, -6) (add and subtract)

So, P' = (2, -6)

6 0
3 years ago
Prove that cos^3x+3cos2x= 4 (cos^6 x-sin^6x)
gavmur [86]
But this isn't true... If x=\dfrac\pi2, you have

\cos^3\dfrac\pi2+3\cos\pi=0-3=-3
4\left(\cos^6\dfrac\pi2-\sin^6\dfrac\pi2\right)=4(0-1)=-4

but of course -3\neq-4.
5 0
3 years ago
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