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2 years ago

Factor the expression below 36a^2-25b^2

Mathematics

2 answers:

Delicious77 [7]2 years ago

6 0

Answer:

6a+5b

Step-by-step explanation:

just olya [345]2 years ago

3 0

Answer:

(6a + 5b)(6a - 5b)

Step-by-step explanation:

Rewrite the expression in the form of a² - b²:

(6a)² - (5b)²

Use the difference of squares (a² - b² = (a + b)(a - b)):

(6a + 5b)(6a - 5b)

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Isaac wants the equation below to have no solution when the missing number is placed in the box.

MatroZZZ [7]

Answer: 4

Step-by-step explanation: To have an equation with no solution you have to get something like 0=1 meaning you have to remove all the variables. In this equation you would distribute to get xy+2y+2x=2x+12+4x where y is the missing number. then combining like terms you get xy+2x+2y=6x+12. Subtracting 2x from both sides you get xy+2y=4x+12. Now to get the variables gone y has to be 4 so that the variables to cancel out. By plugging in 4 you can see this works; 4x+8=4x+12 and by subtracting 4x from both sides you get 8=12 which is not true meaning there is no solution.

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3 years ago

Read 2 more answers

It is known that the life of a particular auto transmission follows a normal distribution with mean 72,000 miles and standard de

scoray [572]

Answer:

a) $P(X$

$P(z$

b) $P(X>65000)=P(\frac{X-\mu}{\sigma}>\frac{65000-\mu}{\sigma})=P(Z>\frac{65000-72000}{12000})=P(z>-0.583)$

$P(z>-0.583)=1-P(Z$

c) $P(X>100000)=P(\frac{X-\mu}{\sigma}>\frac{100000-\mu}{\sigma})=P(Z>\frac{100000-72000}{12000})=P(z>2.33)$

$P(z>2.33)=1-P(Z$

Sicne this probability just represent 1% of the data we can consider this value as unusual.

d) $z=1.28$

And if we solve for a we got

$a=72000 +1.28*12000=87360$

So the value of height that separates the bottom 90% of data from the top 10% is 87360.

Step-by-step explanation:

Previous concepts

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

The Z-score is "a numerical measurement used in statistics of a value's relationship to the mean (average) of a group of values, measured in terms of standard deviations from the mean".

Part a

Let X the random variable that represent the life of a particular auto transmission of a population, and for this case we know the distribution for X is given by:

$X \sim N(72000,12000)$

Where $\mu=72000$ and $\sigma=12000$

We are interested on this probability

$P(X$

And the best way to solve this problem is using the normal standard distribution and the z score given by:

$z=\frac{x-\mu}{\sigma}$

If we apply this formula to our probability we got this:

$P(X$

And we can find this probability using excel or the normal standard table and we got:

$P(z$

Part b

$P(X>65000)$

And the best way to solve this problem is using the normal standard distribution and the z score given by:

$z=\frac{x-\mu}{\sigma}$

If we apply this formula to our probability we got this:

$P(X>65000)=P(\frac{X-\mu}{\sigma}>\frac{65000-\mu}{\sigma})=P(Z>\frac{65000-72000}{12000})=P(z>-0.583)$

And we can find this probability using the complement rule and excel or the normal standard table and we got:

$P(z>-0.583)=1-P(Z$

Part c

$P(X>100000)$

And the best way to solve this problem is using the normal standard distribution and the z score given by:

$z=\frac{x-\mu}{\sigma}$

If we apply this formula to our probability we got this:

$P(X>100000)=P(\frac{X-\mu}{\sigma}>\frac{100000-\mu}{\sigma})=P(Z>\frac{100000-72000}{12000})=P(z>2.33)$

And we can find this probability using the complement rule and excel or the normal standard table and we got:

$P(z>2.33)=1-P(Z$

Sicne this probability just represent 1% of the data we can consider this value as unusual.

Part d

For this part we want to find a value a, such that we satisfy this condition:

$P(X>a)=0.1$ (a)

$P(X$ (b)

Both conditions are equivalent on this case. We can use the z score again in order to find the value a.

As we can see on the figure attached the z value that satisfy the condition with 0.9 of the area on the left and 0.1 of the area on the right it's z=1.28. On this case P(Z<1.28)=0.9 and P(z>1.28)=0.1

If we use condition (b) from previous we have this:

$P(X$

$P(z$

But we know which value of z satisfy the previous equation so then we can do this:

$z=1.28$

And if we solve for a we got

$a=72000 +1.28*12000=87360$

So the value of height that separates the bottom 90% of data from the top 10% is 87360.

5 0

2 years ago

A rectangle’s perimeter and it area have the same numerical value. The width of the rectangle is 3 units. What is the length is

Verdich [7]

Answer:

Step-by-step explanation:

3+3+6+6=18

3*6=18

5 0

2 years ago

the table shows the number of minutes Tim has for lunch and study hall. he calculates that these two periods account for 18% of

EleoNora [17]

Tim spends 500 minutes at the school.

Step-by-step explanation:

Given,

Time for lunch = 45 minutes

Time for study hall = 45 minutes

Total = 45+45 = 90 minutes

This represents 18% of the total minutes Tim spend at school.

Let,

x be the total minutes Tim spend at school.

18% of x = 90 minutes

$\frac{18}{100}x=90\\\\0.18x=90$

Dividing both sides by 0.18

$\frac{0.18x}{0.18}=\frac{90}{0.18}\\x=500$

Tim spends 500 minutes at the school.

Keywords: percentage, division

Learn more about division at:

#LearnwithBrainly

5 0

3 years ago

Michael practiced batting and kept track of his hits. He missed 2 balls but hit 8 balls that were pitched to him. How many balls

trapecia [35]

Answer:

he can be predicted to hit 16 balls

Step-by-step explanation:

because he missed 2 and hit 8, that's 10 balls, times that by 2 it is he missed 4 balls and hit 16, that's 20 balls

3 0

2 years ago