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Eddi Din [679]
2 years ago
7

Factor the expression below 36a^2-25b^2

Mathematics
2 answers:
Delicious77 [7]2 years ago
6 0

Answer:

6a+5b

Step-by-step explanation:

just olya [345]2 years ago
3 0

Answer:

(6a + 5b)(6a - 5b)

Step-by-step explanation:

Rewrite the expression in the form of a² - b²:

(6a)² - (5b)²

Use the difference of squares (a² - b² = (a + b)(a - b)):

(6a + 5b)(6a - 5b)

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3 0
3 years ago
A recent survey showed that in a sample of 100 elementary school teachers, 15 were single. In a sample of 180 high school teache
trapecia [35]

Answer:

By using hypothesis test at α = 0.01, we cannot conclude that the proportion of high school teachers who were single greater than the proportion of elementary teachers who were single

Step-by-step explanation:

let p1  be the proportion of elementary teachers who were single

let p2 be the proportion of high school teachers who were single

Then, the null and alternative hypotheses are:

H_{0}: p2=p1

H_{a}: p2>p1

We need to calculate the test statistic of the sample proportion for elementary teachers who were single.

It can be calculated as follows:

\frac{p(s)-p}{\sqrt{\frac{p*(1-p)}{N} } } where

  • p(s) is the sample proportion of high school teachers who were single (\frac{36}{180} =0.2)
  • p is the proportion of elementary teachers who were single (\frac{15}{100} =0.15)
  • N is the sample size (180)

Using the numbers, we get

\frac{0.2-0.15}{\sqrt{\frac{0.15*0.85}{180} } } ≈ 1.88

Using z-table, corresponding  P-Value is ≈0.03

Since 0.03>0.01 we fail to reject the null hypothesis. (The result is not significant at α = 0.01)

8 0
3 years ago
Solve log x = 2.<br><br> 100<br><br> 1,000<br><br> 2<br><br> 20
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keeping in mind that when the logarithm base is omitted, the base 10 is assumed.

\textit{exponential form of a logarithm} \\\\ \log_a(b)=y \qquad \implies \qquad a^y= b \\\\[-0.35em] ~\dotfill\\\\ \log(x)=2\implies \log_{10}(x)=2\implies 10^2=x\implies 100=x

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2 years ago
What is 18/25 as a decimal
Serga [27]

Answer: 0.72

Step-by-step explanation:

Hope that helps :)

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3 years ago
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