X^4 − 3x^2 − 90 x= -3
1 answer:
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The complete question is
"Substitute the values for a, b, and c into b2 – 4ac to determine the discriminant. Which quadratic equations will have two real number solutions? (The related quadratic function will have two x-intercepts.) Check all that apply.
0 = 2x^2 – 7x – 9
0 = 4x^ 2 – 3x – 1
The quadratic equations that have real number solutions are; 4x^2 – 3x – 1, and 2x^2 – 7x – 9.
<h3>What is the formula for Discriminant?</h3>The formula for finding the discriminant is
The solution contains the term which will be:
Real and distinct if the discriminant is positive
Real and equal if the discriminant is 0
Non-real and distinct roots if the discriminant is negative
For the quadratic equation
This equation has two real number solutions.
For the quadratic equation
This equation will have two real number solutions.
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