Explanation:
This is easily solvable with a for loop. Something like:
(I assume c++)
#include <iostream>
#include <string>
int main() {
take_input: //tag
std::string input;
cin >> input; //take the input
int spaceCount = 0;
char checking;
for(unsigned int i = 0; i == input.length(); ++i) {
checking = spaceCount[i];
if(checking == ' ')
spaceCount++;
}
if(spaceCount >= 1 && input.length >= 5)
std::cout << "Your name is " + input;
else
goto take_input; // reasks for input if the conditions are not met
return 0;
};
**remove all spaces before using the code, the if statements are messed up
Answer:
Steve Jobs, in full Steven Paul Jobs, is the owner of apple company
Explanation:
hope it helps
good day
thank u ✌️
<h2>answer:</h2>
Synchronized method is used to lock an object for any shared resource. When a thread invokes a synchronized method, it automatically acquires the lock for that object and releases it when the thread completes its task.','.
Answer:
- def check_subset(l1, l2):
- status = False
- count = 0
- if(len(l1) > len(l2)):
- for x in l2:
- for y in l1:
- if x == y:
- count += 1
-
- if(count == len(l2)):
- return True
- else:
- return False
-
- else:
- for x in l1:
- for y in l2:
- if x==y:
- count += 1
-
- if(count == len(l1)):
- return True
- else:
- return False
-
- print(check_subset([1,4,6], [1,2,3,4,5,6]))
- print(check_subset([2,5,7,9,8], [7,8]))
- print(check_subset([1, 5, 7], [1,4,6,78,12]))
Explanation:
The key idea of this solution is to create a count variable to track the number of the elements in a shorter list whose value can be found in another longer list.
Firstly, we need to check which list is shorter (Line 4). If the list 2 is shorter, we need to traverse through the list 2 in an outer loop (Line 5) and then create another inner loop to traverse through the longer list 1 (Line 6). If the current x value from list 2 is matched any value in list 1, increment the count variable by 1. After finishing the outer loop and inner loop, we shall be able to get the total count of elements in list 2 which can also be found in list 1. If the count is equal to the length of list 2, it means all elements in the list 2 are found in the list 1 and therefore it is a subset of list 1 and return true (Line 10-11) otherwise return false.
The similar process is applied to the situation where the list 1 is shorter than list 2 (Line 15-24)
If we test our function using three pairs of input lists (Line 26-28), we shall get the output as follows:
True
True
False
The correct answer is A it transfers control to the next loop in the program.
The most valid answer is that the break statement Exits the loop and continues executing the program, but assuming that there are other loops, the control of the program will go to them since the first loop is broken out of.
