Answer:
We use the formula:
S 10 = 8 · [(1/2)^9 - 1] / (1/2 - 1 );
Then, S 10 = 8 · ( 1/512 - 1 ) / ( 1/2 - 1 );
S 10 = 8 · ( - 511 / 512 ) / (-1 / 2 );
S 10 = ( - 511 / 64 ) · ( - 2 );
S 10 = + 511 / 32;
S 10 = 15.96;
Step-by-step explanation:
L = 3 + 2w
Find the width
Area = 54
l × w = 54
(3 + 2w) × w = 54
3w + 2w^2 = 54
2w^2 + 3w - 54 = 0
(2w - 9)(w + 6) = 0
w = 9/2 or w = -6 (width shouldn't be negative)
w = 9/2
w = 4.5 m
Find the length
l = 3 + 2w
l = 3 + 2(4.5)
l = 3 + 9
l = 12 m
The width is 4.5 m, the length is 12 m
The Correct Answer is B
B.False
the number of elements in the union of the A sets is:5(30)−rAwhere r is the number of repeats.Likewise the number of elements in the B sets is:3n−rB
Each element in the union (in S) is repeated 10 times in A, which means if x was the real number of elements in A (not counting repeats) then 9 out of those 10 should be thrown away, or 9x. Likewise on the B side, 8x of those elements should be thrown away. so now we have:150−9x=3n−8x⟺150−x=3n⟺50−x3=n
Now, to figure out what x is, we need to use the fact that the union of a group of sets contains every member of each set. if every element in S is repeated 10 times, that means every element in the union of the A's is repeated 10 times. This means that:150 /10=15is the number of elements in the the A's without repeats counted (same for the Bs as well).So now we have:50−15 /3=n⟺n=45
Answer:
23.6666666667
Step-by-step explanation:
